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2 years ago

11

on a scale of one to 100, your teacher crankiness is directly proportional to the number of students talking while she is talkin

g, the teachers crankiness index is 5. What is her crankiness index when 6 students are talking?

1 answer:

alexandr1967 [171]2 years ago

5 0

Answer:

30 (random guess)

Step-by-step explanation:

You might be interested in

(Please correct answers only) (Will mark brainliest)

sergij07 [2.7K]

The answer is B., valid because people were chosen randomly
This would make it a valid survey
Hope this helps!
;3

8 0

2 years ago

Read 2 more answers

Adult female height is normally distributed with a mean of 65.3 inches and a standard deviation of 2.32 inches. a) If an adult f

emmasim [6.3K]

Answer:

0.0423 is the probability that the adult female has a height less than 61.3 inches.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 65.3 inches

Standard Deviation, σ = 2.32 inches

We are given that the distribution of adult female height is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(adult female has a height less than 61.3 inches)

$P( x < 61.3) = P( z < \displaystyle\frac{61.3 - 65.3}{2.32}) = P(z < -1.7241)$

Calculation the value from standard normal z table, we have,

$P(x < 61.3) =0.0423 = 4.23\%$

0.0423 is the probability that the adult female has a height less than 61.3 inches.

5 0

3 years ago

What is the estimate of 615

Yakvenalex [24]

Estimate to nearest hundreds is 600

Estimate to nearest tens is 610 or 520

8 0

3 years ago

Read 2 more answers

The arm span and foot length were both measured (in centimeters) for each of 20 students in a biology class. The computer output

irina1246 [14]

Answer:

The guy above me is completely wrong hahaha.

The correct answer should have a 63%.

It's probably D. The terminology is a little confusing.

The equation of the output looks like:

-7.611 + .186(x) = y

x --> Arm span

y --> Foot span

The linear relationship is formed with the armspan.

6 0

2 years ago

33 * 32 * 31 * 30 * 3−1 * 3−2

4vir4ik [10]

Answer:

8838715

Step-by-step explanation:

hope this helps:)

3 0

2 years ago