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ololo11 [35]
3 years ago
8

What is 3x + 9 = 2.5x + 14?

Mathematics
2 answers:
balandron [24]3 years ago
7 0

Answer:

10

Step-by-step explanation:

3x + 9 = 2.5x + 14

3x -2.5 = 14 - 9

0.5x = 5

x = 2 X 0.5x

so x = 2 X 5 = 10

Rus_ich [418]3 years ago
4 0

3x+9=2.5x+14. =>

0.5x=5 => x=10.

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Solve this rational equation ​
tino4ka555 [31]

Answer:

<h2>x = -1</h2>

Step-by-step explanation:

\text{Domain:}\\\\x-4\neq0\ \wedge\ x-2\neq0\ \wedge\ x^2-6x+8\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ x^2-4x-2x+8\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ x(x-4)-2(x-4)\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ (x-4)(x-2)\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ x-4\neq0\ \wedge\ x-2\neq0\\\\\boxed{D:x\neq4\ \wedge\ x\neq2}

\dfrac{1}{x-4}+\dfrac{x}{x-2}=\dfrac{2}{x^2-6x+8}\\\\\dfrac{1(x-2)}{(x-4)(x-2)}+\dfrac{x(x-4)}{(x-4)(x-2)}=\dfrac{2}{(x-4)(x-2)}\\\\\dfrac{x-2+x(x-4)}{(x-4)(x-2)}=\dfrac{2}{(x-4)(x-2)}\iff x-2+x(x-4)=2\\\\x-2+(x)(x)+(x)(-4)=2\\\\x-2+x^2-4x=2\qquad\text{subtract 2 from both sides}\\\\x^2-3x-4=0\\\\x^2-4x+x-4=0\\\\x(x-4)+1(x-4)=0\\\\(x-4)(x+1)=0\iff x-4=0\ \wedge\ x+1=0\\\\x-4=0\qquad\text{add 4 to both sides}\\x=4\notin D\\\\x+1=0\qquad\text{subtract 1 from both sides}\\x=-1\in D

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Evaluate the function for x = –8.<br> f(x) = –2x – 12<br> a. 28<br> b. –40<br> c. –28<br> d. 4
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<span>f(x) = –2x – 12 ; x = -8 f(-8) = -2(-8) - 12 f(-8) = 16 - 12 f(-8) = 4 The function for x is: D. 4</span>
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