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3 years ago

How to solve 15=x-3 ;_;

2 answers:

5 0

The top answer is right, it’s 18.
15=x-3
you’d add 3 to 3 to get rid of it (because it’s -3) and add it to also 15. 15+3= 18 so x=18
15=18-3

Vitek1552 [10]3 years ago

3 0

X= 18

So that you can help yourself better use Math-way!!

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Find the equation of the linethe line passes through the points (5,2) and (-4,-4)

almond37 [142]

Answer:

$y = \frac{2}{3}x - \frac{4}{3}$

Step-by-step explanation:

first find the slope using the above points then use the slope formula to calculate the slope

$m = \frac{y2 - y1}{x2 - x1} \\ \frac{2 - - 4}{5 - - 4} = \frac{2 + 4}{5 + 4} = \frac{6}{9} = \frac{2}{3}$

substitute ⅔ for m and one of the above points into the y-intercept form of the equation for a line and solve for b

$y = mx + b \\ 2 = \frac{2}{3} (5) + b \\ 2 = \frac{10}{3} + b \\ 2 - \frac{10}{3} = b \\ \frac{6}{3} - \frac{10}{3} = b \\ b = - \frac{4}{3}$

substitute the slope and the value for b into the equation to get the answer

$y = \frac{2}{3} x - \frac{4}{3}$

4 0

3 years ago

What is a formula for the nth term of the given sequence?

lakkis [162]

Answer: option D is the correct answer.

Step-by-step explanation:

The given sequence is a geometric sequence because the consecutive terms differ by a common ratio.

The formula for determining the nth term of a geometric progression is expressed as

an = a1r^(n - 1)

Where

a1 represents the first term of the sequence.

r represents the common ratio.

n represents the number of terms.

From the information given,

a1 = 36

r = 12/36 = 4/12 = 1/3

Therefore, the formula for the nth term of the sequence is

an = 36 × 1/3^(n - 1)

an = 36 × 3^-1(n - 1)

an = 36 × 3^(-n + 1)

an = 36 × 3^(1 - n)

6 0

3 years ago

In which two of these numbers does the digit

monitta

Answer:

85.62

Step-by-step explanation:

Hope this helps!

If not, I am sorry.

7 0

2 years ago

Read 2 more answers

Which is a correct first step for solving this equation?<br> - 32 + 2 - 52 - 7 = 4x + 2

MArishka [77]

Answer:

-8x - 5 = 4x + 2

6 0

2 years ago

Polygon ABCD is dilated, rotated, and translated to form polygon A′B′C′D′. The endpoints of AB are at (0, -7) and (8, 8), and th

Anton [14]

Rotation and translation are rigid transformations, they don't change figure sizes. Dilation change figure sizes increasing or decreasing them by scale factor.

First, find AB and A'B' by the formula:

$AB=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}= \sqrt{(8-0)^2+(8-(-7))^2}=\sqrt{8^2+15^2}=\sqrt{64+225}=\sqrt{289}=17,\\ \\A'B'=\sqrt{(x_{B'}-x_{A'})^2+(y_{B'}-y_{A'})^2}= \sqrt{(2-6)^2+(1.5-(-6))^2}=\sqrt{4^2+7.5^2}=\sqrt{16+56.25}=\sqrt{72.25}=8.5.$

As you can see AB=2A'B'. This means that the segment AB was decreased twice to form segment A'B'. Then the scale factor is 1/2.

8 0

3 years ago