2mn - 3m + 8n - 12
Let's group the first two terms together and the last two:
2mn - 3m and 8n - 12
In the first group, m is the greatest common factor.
m(2n - 3)
In the second group, 4 is the greatest common factor.
4(2n - 3)
Therefore, (m + 4) and (2n - 3) are our factors. Our missing term is 2n.
Y=1/2x-6
y=86
86=1/2x-6
1/2x=92
x=184
The original price was $184
Answer:
it is C.
Step-by-step explanation:
we can pretty much split the middle part into two trapezoids. Check the picture below.
so we really have one trapezoid and one square, each twice, so simply let's get the area of the trapezoid and sum it up with the area of the square, twice, and that's the area of the shape.
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{\textit{parallel sides}}{bases}\\[-0.5em] \hrulefill\\ h=5\\ a=3\\ b=7 \end{cases}\implies A=\cfrac{5(3+7)}{2}\implies A=25 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{sum of areas}}{[25+(3\cdot 3)]}\cdot \stackrel{twice}{2}\implies [34]2\implies \underset{in^2}{68}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7B%5Ctextit%7Bparallel%20sides%7D%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20h%3D5%5C%5C%20a%3D3%5C%5C%20b%3D7%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B5%283%2B7%29%7D%7B2%7D%5Cimplies%20A%3D25%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bsum%20of%20areas%7D%7D%7B%5B25%2B%283%5Ccdot%203%29%5D%7D%5Ccdot%20%5Cstackrel%7Btwice%7D%7B2%7D%5Cimplies%20%5B34%5D2%5Cimplies%20%5Cunderset%7Bin%5E2%7D%7B68%7D)
Answer:
750 ft²
Step-by-step explanation:
.Given :
Charge per ft² = 50¢ = $0.5
Total cost = ((charge per ft² * number of ft²) + cost of paint)
Given that :
Paint cost = $100
Total cost = $475
Number of ft² = x
Plugging values into the equation :
475 = (( 0.5 * x) + 100)
475 = 0.5x + 100
475 - 100 = 0.5x
375 = 0.5x
x = 375 / 0.5
x = 750 ft²
