Let us say that,
<span>A = perimeter of football field of the 1st
school</span>
B = perimeter of football field of the 2nd school
C = perimeter of football field of the 3rd school
So that:
A = 320 m
B = 360 m
C = 400 m
So the first thing we have to do to find for the minimum
laps to make is to divide every perimeter by the smallest one, therefore divide
all by 320 m, hence:
A’ = 1
B’ = 1.125
C’ = 1.25
Now multiply everything by a number such that all laps
will be a whole number, in this case multiply everything by 8:
A’ = 8
B’ = 9
C’ = 10
Hence the laps to run are:
<span>8, 9 and 10</span>
This is the equation
185+185(2)+185-50
185+370+185-50 (you multiply 185 times 2 first)
370+370-50 (you add 185 to 185)
740-50 (you add 370 to 370)
740-50=690
There were 690 visitors during these three days.
Answer:
<h2>18</h2>
Step-by-step explanation:

Answer:
C
Step-by-step explanation:
Using the rules of logarithms
loga + logb = log(ab)
loga - logb = log(
)
log
⇔ nlogx
Given
4lnx + ln3 - lnx
= 3lnx + ln3
= lnx³ + ln3
= ln(x³ × 3)
= ln(3x³) → C
Answer:g/c
Step-by-step explanation: