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3 years ago

The vertex form of the equation of a parabola is y= 3(x - 4)^2 -22. What is the standard form of the equation

Mathematics

2 answers:

Sunny_sXe [5.5K]3 years ago

8 0

Answer:

option A

Step-by-step explanation:

We can find the standard form by expanding the equation:

y = 3(x-4)^2 - 22

y = 3(x^2 - 8x + 16) - 22

y = 3x^2 - 24x + 48 - 22

y= 3x^2 - 24x + 26

So the correct option is option A

shutvik [7]3 years ago

3 0

Answer:

option A) y= 3x²-24x+26 ~apex

Step-by-step explanation:

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Answer:

y=-2x^2-4

Step-by-step explanation:

The parabola is wider than it's parent function, y = x^2. Therefore the coefficient, of x^2 (when you refer to quadratic equations it's a) should be greater than 1. Let's take 2.

y = 2x^2

Now it is reflected across the x-axis, so the equation turns to y = -2x^2. The vertex is shifted down 4. Note that it is shifted down, along the y-axis. This makes 'c' (again quadratic equations) -4.

Final Equation: y=-2x^2-4

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3 years ago

Point R is on line segment QS. Given QS= 5x-2, QR= 3x-6, and RS=4x-2, determine the numerical length of RS.

pashok25 [27]

Answer:

The numerical length of RS is 10 units

Step-by-step explanation:

* Lets explain How to solve the problem

- Point R is on line segment QS

- The length of QS is (5x - 2)

- The length of QR is (3x - 6)

- The length of RS is (4x - 2)

- The length of QS is the sum of the lengths of QR and RS

∵ QS = QR + RS

∴ (5x - 2) = (3x - 6) + (4x - 2)

- Simplify the right hand side by adding like terms

∴ 5x - 2 = (3x + 4x) + (-6 + -2)

∴ 5x - 2 = 7x + -8 ⇒ (+)(-) = (-)

∴ 5x - 2 = 7x - 8

- Add 8 for both sides

∴ 5x + 6 = 7x

- Subtract 5x from both sides

∴ 6 = 2x

- Divide both sides by 2

∴ x = 3

- To find the length of RS substitute the value of x in its expression

∵ RS = 4x - 2

∵ x = 3

∴ RS = 4(3) - 2 = 12 - 2 = 10

∴ The numerical length of RS is 10 units

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4 years ago