Answer:
The required sample size for the new study is 801.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

25% of all adults had used the Internet for such a purpose
This means that 
95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
What is the required sample size for the new study?
This is n for which M = 0.03. So






Rounding up:
The required sample size for the new study is 801.
To make it easier just assume there is no decimal point then just work out the 32÷4 where we know that 4 goes into 32 8 times so you get 8 remember the decimal point and since it was one decimal place you will push the decimal over to the left of 8 and that is how you get 0.8
<h2>GOOD LUCK CHUCK :)))))))))</h2>
I think it would be the second question!