Question

What is the standard equation of the circle with radius 5 and the center (-3, -4)?

Answer 1

ANSWER

${(x + 3)}^{2} + {(y + 4)}^{2} = 25$

EXPLANATION

The equation of a circle with center (h,k) and radius r units is given by:

${(x - h)}^{2} + {(y - k)}^{2} = {r}^{2}$

From the given information the center of the circle is (-3,-4) and the radius is r=5 units.

We substitute the known values to obtain:

${(x - - 3)}^{2} + {(y - - 4)}^{2} = {5}^{2}$

We simplify to get:

${(x + 3)}^{2} + {(y + 4)}^{2} = 25$

Therefore the equation of the circle in standard form is:

${(x + 3)}^{2} + {(y + 4)}^{2} = 25$

Answer 2

Answer:

(x+3)² + (y+4)²=25

Step-by-step explanation:

The question is on equation of a circle

The distance formula is given by;

√(x-h)²+ (y-k)²=r

The standard equation of  circle is given as ;

(x-h)²+ (y-k)²=r²

The equation of this circle with center (-3, -4) and radius 5 will be;

(x--3)² + (y--4)²=5²

(x+3)² + (y+4)²=25