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dlinn [17]
4 years ago
6

Can 15x-10 be factored

Mathematics
2 answers:
Anna [14]4 years ago
6 0
Yes because removing the common factor is important. There are a few steps, then you can factor by regrouping. Hope this helps.
masya89 [10]4 years ago
6 0
Yes. As you can see, 15 and 10 are both factors of 5. So, if you take out a 5, you're left with 5(3x-2).
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What is the value of m in the equation 1/2m - 3/4n = 16, when n = 8?
Tresset [83]

Answer: m= 44

Step-by-step explanation:

1/2m - 3/4n = 16    when n is 8  put it into the equation and solve for m.

1/2m - 3/4(8) = 16

1/2m - 6 = 16  

          +6  +6

1/2m = 22

m = 44

3 0
3 years ago
Read 2 more answers
What is 7 over (fraction bar) (8×4)+90÷9 ÷ (6^3)^-2 × 9 over (fraction bar) 6(5+4) = ?????
amid [387]
The answer is:  " 36 " .
_______________________________
Note:  " (8 * 4) + 90 ÷ 9 " =  " (8 * 4) + (90 ÷ 9) " = "32 + 10 = 42" .

We can rewrite the "fraction":
 
7 / [ (8 * 4) + 90 ÷ 9 ] ;  as:  \frac{7}{42} ;  

and can reduce this value to (and rewrite as):  " \frac{1}{6} " ; 
    { since:  " \frac{7}{42}  =  \frac{7/7}{42/7}  = \frac{1}{6}" .}.

Note:  The "fraction" : \frac{9}{6(5+4)} ;  the "9/6" cancel to "3/2" ; 
  {Since:  "9÷3 = 3" ; and since:  "6÷3 = 2" ).

So rewrite:  \frac{9}{6(5+4)} ; as:  

\frac{3}{2(5+4)} ;

Note:  \frac{3}{2(5+4)}  ;

       =   \frac{3}{2(9)} ;

       =   \frac{3}{18} ;

→  Note:   \frac{3}{18} ;  can be reduced to; & rewritten as:

             " \frac{1}{6} " ;

→ {since: " \frac{3}{18} =  \frac{3/3}{18/3} ;
               
                                                      =   \frac{1}{6} ;
______________________________

Note that: (6²) ⁻² = 6⁽ ² * ⁻²⁾ = 6⁻ ⁴  ;
    
                            =  \frac{1}{6^4} ;
_________________________________________________________
So, we can rewrite our expression as:

 \frac{1}{6}  ÷  \frac{1}{6^4}  *  \frac{1}{6} ;
_________________________________________________________
Note:  
_________________________________________________________
 \frac{1}{6}  ÷  \frac{1}{6^4}  *  \frac{1}{6} ;

= ( \frac{1}{6}  ÷  \frac{1}{6^4} ) *  \frac{1}{6} ; 

= ( \frac{1}{6}  *   \frac{6^4}{1} ) *  \frac{1}{6} ;

________________________________________________________
Start with :
________________________________________________________
   → ( \frac{1}{6}  *   \frac{6^4}{1} ) ;

            The "6" in  the  " \frac{1}{6} " ;  cancels to a "1" ; 
       and the "6⁴ " in the "  \frac{6^4}{1} ) " ; cancels to a "6³ " ;

         → {Since:  "6⁴ / 6  =  6⁴ / 6¹  =  6⁽⁴ ⁻ ¹⁾  = 6³ ;

         → and we have:   \frac{1}{1}  *  \frac{6^3}{1} ;
 
         →  The " \frac{1}{1} " can be eliminated; since "1÷1= 1 " ;
               and since: any value, divided by "1", equal that same value; & since "any                       value, multiplied by "1"; equals that same value" ;
________________________________________________________
 We have:  " 6³ " .
________________________________________________________

Now, we multiplied this value, " 6³ " , by  " \frac{1}{6} " ;

→  6³  *  \frac{1}{6}  ;

     =  \frac{6^3}{1} * \frac{1}{6}  ;

Note:  The "6³ " cancels out to "6² " ;  and the "6" cancels out to "1" ; 

          {since:  "6³ ÷ 6 = 6³ ÷ 6¹ = 6⁽³ ⁻ ¹⁾ = 6² " ;
            and since:  "6 ÷ 6 = 1 "  ; ________________________________________________________
→ The answer is:  6² = 6 * 6 = 36 ;
________________________________________________________
The answer is:  " <span>36 " .</span>
________________________________________________________
7 0
3 years ago
Solve the equations below. Give exact solutions only. Show your work.
Nikolay [14]

Step-by-step explanation:

remember, the general formula to solve a quadratic equation ax² + bx + c = 0 is

x = (-b ± sqrt(b² - 4ac))/(2a)

a)

I think there is a typo, and this should be

5x² - 7x = 72

5x² -7x - 72 = 0

x = (7 ± sqrt(49 - -1440))/10 = (7 ± sqrt(1489))/10

x1 = (7 + sqrt(1489))/10

x2 = (7 - sqrt(1489))/10

b)

x(x + 2) = 5

x² + 2x - 5 = 0

x = (-2 ± sqrt(4 - -20))/2 = (-2 ± sqrt(24))/2 =

= (-2 ± sqrt(4×6))/2 = (-2 ± 2×sqrt(6))/2 =

= -1 ± sqrt(6)

x1 = -1 + sqrt(6)

x2 = -1 - sqrt(6)

c)

3x² + 2x - 4 = 0

x = (-2 ± sqrt(4 - -48))/6 = (-2 ± sqrt(52))/6 =

= (-2 ± sqrt(4×13))/6 = (-2 ± 2×sqrt(13))/6 =

= (-1 ± sqrt(13))/3

x1 = (-1 + sqrt(13))/3

x2 = (-1 - sqrt(13))/3

4 0
3 years ago
Greater number832458or 83250
aksik [14]
832458 is the greater number
3 0
3 years ago
Read 2 more answers
State of the number 49/9 (square root) is a rational or irrational
lina2011 [118]
Hey there!!

49/9 = 7
is a rational number as it has a definite answer 7.

Hope it helps you.
5 0
4 years ago
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