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2 years ago

A regular pentagon has a perimeter of 15x+35 What is the length of one side of the pentagon?

Mathematics

1 answer:

valentinak56 [21]2 years ago

8 0

Answer:

-3.5 or -7/2

Step-by-step explanation:

Pentagons have five sides, so 15x+35

15x+35=5

subtract 35

15x+35-35=5x-35

simplify

15x=5x-35

subtract 5x

15x-5x=5x-35-5x

simplify

10x=-35

divide by 10

$\frac{10x}{10}=\frac{-35}{10}$

simplify

$x=-\frac{7}{2}$ or also -3.5

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3 years ago

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Answer:

a) $E(Y)= \sum_{i=1}^n Y_i P(Y_i)$

And replacing we got:

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Step-by-step explanation:

Previous concepts

In statistics and probability analysis, the expected value "is calculated by multiplying each of the possible outcomes by the likelihood each outcome will occur and then summing all of those values".

The variance of a random variable Var(X) is the expected value of the squared deviation from the mean of X, E(X).

And the standard deviation of a random variable X is just the square root of the variance.

Solution to the problem

Part a

We have the following distribution function:

Y 0 1 2 3

P(Y) 0.45 0.2 0.3 0.05

And we can calculate the expected value with the following formula:

$E(Y)= \sum_{i=1}^n Y_i P(Y_i)$

And replacing we got:

$E(Y) = 0*0.45 +1*0.2 +2*0.3 +3*0.05= 0.95$

Part b

For this case the new expected value would be given by:

$E(80Y^2)= \sum_{i=1}^n 80Y^2_i P(Y_i)$

And replacing we got

$E(80Y^2) =80[ 0^2*0.45 +1^2*0.2 +2^2*0.3 +3^2*0.05]= 148$

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2 years ago

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just olya [345]

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