(-3)^2 = 9
-3^2 = -9
Hope this helps!
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Answer: 42 feet
Step-by-step explanation:
The solution is in the attachment
I prefer D.
It's clear that Kevin took (1/4)x.
Keith took (1/4)x -> kevin's amount
* 2 -> twice.
-1 -> 1 less.
So Kevin + Keith = (1/4)x + (1/4)x * 2 - 1 = (3/4)x - 1.
Answer:
Step-by-step explanation:
Differentiate:
Substitute 
into 
:
Therefore, 68 is the gradient of the tangent line at x=7:
when , 
