50 Points help, please!!Angelica and Graciella are working together to find the sine and cosine of Latex: \angle A
1 answer:
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You have to complete the square on this to get it into standard form of a circle. Move the 8 over to the other side because that's part of the radius. Group together the x terms, take half the linear term which is 8, square it and add it in to both sides. Half of 8 is 4, 4 squared is 16, so add in 16 to both sides. I'll show you in a sec. You don't need to do anything to the y squared term. This just means that the center of the circle does not move up or down, only side to side, right or left. Here's your completing the square before we simplify it down to its perfect square binomial. 
. Now break down the parenthesis into the perfect square binomial and do the addition of the right: 
. This is the standard form of a circle that has a center of (4, 0) and a radius of 
By definition, the average change of rate is given by:
We will calculate AVR for each of the functions.
We have then:
f(x) = x^2 + 3x interval: [-2, 3]:
f(x) = 3x - 8 interval: [4, 5]:
f(x) = x^2 - 2x interval: [-3, 4]
f(x) = x^2 - 5 interval: [-1, 1]
Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x
We will calculate AVR for each of the functions.
We have then:
f(x) = x^2 + 3x interval: [-2, 3]:
f(x) = 3x - 8 interval: [4, 5]:
f(x) = x^2 - 2x interval: [-3, 4]
f(x) = x^2 - 5 interval: [-1, 1]
Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x