First set up a linear equation and using the x and y values in the table see if it solves.
It doesn't solve so we know it isn't linear. ( I won't show all those steps because they aren't needed.)
Using the quadratic formula y = ax^2 +bx +c
Build a set of 3 equations from the table:
C is the Y intercept ( when X is 0), this is shown in the table as 6
Now we have y = ax^2 + bx + 6
-2.4 =4a-2b +6
1.4 = a-b +6
Rewrite the equations
a=b/2 -2.1
1.4 = b/2-2.1 +6
b = 5
a = 5/2 -2.1 = 0.4
replace the letters to get y = 0.4x^2 + 5x +6
90% of 100 = 0.9 x 100 = 90
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Answer: The visitor can see 90 ships.
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Answer:
Doing the same for me :(
Step-by-step explanation:
Answer:
Part 1) The area is ![A=4,069.44\ in^{2}](https://tex.z-dn.net/?f=A%3D4%2C069.44%5C%20in%5E%7B2%7D)
Part 2) The circumference is ![C=226.08\ in](https://tex.z-dn.net/?f=C%3D226.08%5C%20in)
Step-by-step explanation:
step 1
Find the area
we know that
The area of a circle (circular tablecloth) is equal to
![A=\pi r^{2}](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E%7B2%7D)
we have
------> the radius is half the diameter
![\pi =3.14](https://tex.z-dn.net/?f=%5Cpi%20%3D3.14)
substitute
![A=(3.14)(36)^{2}](https://tex.z-dn.net/?f=A%3D%283.14%29%2836%29%5E%7B2%7D)
![A=4,069.44\ in^{2}](https://tex.z-dn.net/?f=A%3D4%2C069.44%5C%20in%5E%7B2%7D)
step 2
Find the circumference
we know that
The circumference of a circle (circular tablecloth) is equal to
![C=\pi D](https://tex.z-dn.net/?f=C%3D%5Cpi%20D)
we have
![\pi =3.14](https://tex.z-dn.net/?f=%5Cpi%20%3D3.14)
substitute
![C=(3.14)(72)](https://tex.z-dn.net/?f=C%3D%283.14%29%2872%29)
![C=226.08\ in](https://tex.z-dn.net/?f=C%3D226.08%5C%20in)
Asimply measure its length. What else could you measure? After all, length is the only feature a segment has. You’ve got your short, your medium, and your long segments.
Step-by-step explanation:
length