Answer: You'll be able to do this!
Step-by-step explanation:
I will be so proud of you if you complete it
Answer:
C. 0
Step-by-step explanation:
–4j^2 + 3j – 28 = 0
The discriminant is b^2-4ac if >0 we have 2 real solutions
=0 we have 1 real solutions
<0 we have 2 imaginary solutions
a = -4, b =3 c = -28
b^2 -4ac
(3)^2 - 4(-4)*(-28)
9 - 16(28)
9 -448
This will be negative so we have two imaginary solutions.
Therefore we have 0 real solutions
If B is the midpoint of AC, then AB=BC. It is also BC=AC-AB
AB = x + 6
AC = 5x - 6
BC = (5x - 6) - (x + 6)
We can kinda use distributive property, like this:
BC = 5x - 6 -x - 6
Combine like terms:
BC = 4x - 12
To verify, we can add AB and BC to see if their sum is equal to AC.
(x + 6) + (4x - 12) = 5x - 6
If we are correct, this equation will be true.
x + 6 + 4x - 12 = 5x - 6
Combine like terms:
6 + 5x - 12 = 5x - 6
5x - 6 = 5x - 6
It's correct!
BC = 4x - 12. Final Answer.
Let me know if you have any questions about this! :)
Answer:
(x+1.2)2=68.3
Step-by-step explanation:
(x+1.2)2=68.3
Answer:
9
Step-by-step explanation:
Using the rules of logarithms
log
= nlogx
b = 1
Then
= 9 x
= 9
