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alisha [4.7K]
3 years ago
8

> 5" align="absmiddle" class="latex-formula">
I've tried solving this inequality multiple times and I just can't get it right. I don't know what I'm doing wrong. please help​
Mathematics
1 answer:
ExtremeBDS [4]3 years ago
3 0

The absolute value is defined as

|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x

So for example, if <em>x</em> = 3, then |<em>x</em>| = |3| = 3, since 3 is positive. On the other hand, if <em>x</em> = -5, then |<em>x</em>| = |-5| = -(-5) = 5, since -5 is negative. The absolute value is always positive.

For the inequality |7 + 8<em>x</em>| > 5, you consider the two cases where the argument to the absolute value (the expression you find inside the bars) is either positive or negative.

• If 7 + 8<em>x</em> ≥ 0, then |7 + 8<em>x</em>| = 7 + 8<em>x</em>, so that

|7+8x|>5\implies 7+8x>5 \implies 8x>-2 \implies x>-\dfrac14

• Otherwise, if 7 + 8<em>x</em> < 0, then |7 + 8<em>x</em>| = -(7 + 8<em>x</em>), so that

|7+8x|>5\implies-(7+8x)>5\implies7+8x

The solution to the inequality is the union of these two intervals.

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28-4x

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Step 1: Open most inner bracket and simplify

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2 years ago
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Answer:

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Step-by-step explanation:

since you're working with the Pythagorean theorem, you should know that a^2+b^2=c^2, therefore, we know that we only have two sides. we have a and c. we know that a = 42 and c = 58, giving us the equation of 42^2+b^2=58^2,

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