Answer:
56.39 nm
Step-by-step explanation:
In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,
where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...
Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.
In order to have its longest constructive reflection at the red end (700 nm)
Here we take m=0.
Similarly for the constructive reflection at the blue end (400 nm)
Hence the thickness difference should be
The limit as a definite integral on the interval 
on [2π , 4π] is 
.
<h3>
What is meant by definite integral?</h3>
A definite integral uses infinitesimal slivers or stripes of the region to calculate the area beneath a function. Integrals can be used to represent a region's (signed) area, the cumulative value of a function changing over time, or the amount of a substance given its density.
Definite integral, a term used in mathematics. is the region in the xy plane defined by the graph of f, the x-axis, and the lines x = a and x = b, where the area above the x-axis adds to the total and the area below the x-axis subtracts from the total.
If an antiderivative F exists for the interval [a, b], the definite integral of the function is the difference of the values at points a and b. The definite integral of any function can also be expressed as the limit of a sum.
Let the equation be
substitute the values in the above equation, we get
= on [2π, 4π],
simplifying the above equation
To learn more about definite integral refer to:
brainly.com/question/24353968
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Okay post them 1 at a time
Distance = velocity * time
= 3 * 10^8 * 8.64 * 10^4
= 2.592 * 10^13 meters (answer)
Answer:
Exact form: 37/8 Decimal form: 4.625 Mixed number form: 4 5/8
Step-by-step explanation:
dd the whole numbers first.
4+\frac{1}{4}+\frac{3}{8}
4+
4
1
+
8
3
2 Find the Least Common Denominator (LCD) of \frac{1}{4},\frac{3}{8}
4
1
,
8
3
. In other words, find the Least Common Multiple (LCM) of 4,84,8.
LCD = 88
3 Make the denominators the same as the LCD.
4+\frac{1\times 2}{4\times 2}+\frac{3}{8}
4+
4×2
1×2
+
8
3
4 Simplify. Denominators are now the same.
4+\frac{2}{8}+\frac{3}{8}
4+
8
2
+
8
3
5 Join the denominators.
4+\frac{2+3}{8}
4+
8
2+3
6 Simplify.
4\frac{5}{8}
4
8
5
