Answer with Step-by-step explanation:
We are given that a sample space
S={a,b,c,d,e}
P(a)=0.1
P(b)=0.1
P(c)=0.2
P(d)=0.4
P(e)=0.2
a.A={a,b,c}
P(A)=P(a)+P(b)+P(c)
P(A)=0.1+0.1+0.2=0.4
b.B={c,d,e}
P(B)=P(c)+P(d)+P(e)=0.2+0.4+0.2=0.8
c.A'=Sample space-A={a,b,c,d,e}-{a,b,c}={d,e}
P(A')=P(d)+P(e)=0.4+0.2=0.6
d.
={a,b,c,d,e}
=P(a)+P(b)+P(c)+P(d)+P(e)=0.1+0.1+0.2+0.4+0.2=1
e.
={c}

Answer:

Step-by-step explanation:
Part A ;

Part B ;

1,000,000/50=20,000 so 20,000 50-passenger buses. Hope this helped!
Answer:
you didn't put the whole question , sorry, i was gonna answer.
Answer:
A. $18
B. $200
C. 
Step-by-step explanation:
Function:

<u>Parts A and B:</u>
The price that generates the maximum profit is ate vertex of parabola. Find the coordinates of the vertex:

The price that generates the maximum profit is $18
The maximum profit is $200
<u>Part C:</u>
The company breaks even when the profit is positive. From the graph of the function you can see that the graph of the function is over p-axis for all
, so the positive profit is for 
In p=16 and p=20, the profit is 0 and when p<16 and p>20, there will be a loss.