<h2><u>
Heart and lungs:</u></h2>
The upper chamber of the heart is called atrium and lower chamber of the heart is called ventricles.
The blood circulation in the heart is basically under the functioning of three blood vessels namely:
<h3><u>Arteries:
</u></h3>
- They start with the aorta, the huge vein leaving the heart.
- Veins divert oxygen-rich blood from the heart to the majority of the body's tissues.
- They branch a few times, decreasing and littler as they convey blood more remote from the heart.
<h3><u>Capillaries:
</u></h3>
- These are little; flimsy blood vessels that associate the arteries and the veins.
- Their dainty dividers permit oxygen, supplements, carbon dioxide, and other waste items to go to and from our organ's cells.
<h3><u>Veins:
</u></h3>
- These are the blood vessels that return blood to the heart; this blood needs (oxygen-poor) and is wealthy in waste items that are to be discharged or expelled from the body.
- Veins become bigger and bigger as they draw nearer to the heart.
- The unrivaled vena cava is the huge vein that brings blood from the head and arms to the heart, and the second rate vena cava brings blood from the mid-region and legs into the heart.
Answer:
See the answer below
Explanation:
<em>Recall that the law of dilution states that the number of moles before dilution must be equal to the number of moles after dilution.</em>
Mathematically,
molarity x number of moles before dilution = molarity x number of moles after dilution.
For solution A: final molarity = 3 mM, final volume = 2mL, initial molarity of KMnO4 = 10 mM
Applying the equation:
10 x initial volume = 3 x 2
initial volume = 6/10 = 0.6
<u>Hence, Tube A should be made with 0.6 mL of 10 mM KMnO4 stock and 1.4 mL of distilled water to give a solution of 2 mL 3 mM KMnO4.</u>
For solution B:final molarity = 8 mM, final volume = 2 mL, initial molarity = 10 mM
10 x initial volume = 8 x 2
initial volume = 16/10 = 1.6
<u>Hence, Tube B should be made with 1.6 mL of 10 mM KMnO4 stock and 0.4 mL of distilled water to give a solution of 2 mL 8mM KMnO4. </u>
Answer:
Zygomatic Process occurs on temporal bone.
Explanation:
Cheek bone is formed by the zygomatic process. Zygomatic process occurs anteriorly in front of mandibular fossa and posteriorly by external acoustic measles muscle.
Temporal bone is involved in the zygomatic process. The temporal bone extends towards the sides of the skull and lies over the opening of ear. The jugal point is present on the upper side of zygomatic arch.
I believe its (B). Giving up a neutron
Answer:
The correct answer will be option A.
Explanation:
The electrical impulses are generated in the sino-atrial node or SA node, a mass of cells which generates impulse in the upper atrium.
This electrical impulse transmits from the sino-atrial node to the atrio-ventricular node in the lower portion of the upper atrium through the internodal pathway- the pathway composed of atrial cells.
Once the impulse reaches the AV node, it is transferred to the ventricular portion of the heart through Bundle of His presence in the ventricular septum. This bundle of his divides into left and right ventricles through bundle branches and stimulates both the ventricles.
Thus, option-A is the correct answer.
