I think its 10,000 pounds, you can use a tons to pounds caculator to check
Answer:
Force = - 2.1 Newton
Step-by-step explanation:
According to question ,
The value of Spring constant , K = 7 N/m Newton per meter
And the spring is extended up to 0.3 meter
The Force experience on the spring is calculated from the Hook's Law
<u>The principal state that , the force applied on spring to extend or compress the spring to some distance is proportion to that distance. </u>
Let the force be F
So, F = - K X
where K is spring constant and X is its displacement
Negative sign shows displacement of spring once it is stretched
And K is spring constant
So ,Force = ( - ) 7 × 0.3
I.e Force = - 2.1 Newton Answer
Answer:
Is the answer, if you want it simplified then, 
Step-by-step explanation:
Answer:
Geometric Mean = 9.17
Step-by-step explanation:
Here,
a = 7
b = 12
Geometric mean = root(ab)
= root( 7 x 12)
= root(84)
= 9.17
Answer:
Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.
The total cost of both games is:
X + Y
We know that both games cost just above AED 80
Then:
X + Y > AED 80
From this, we want to prove that at least one of the games costed more than AED 40.
Now let's play with the possible prices of X, there are two possible cases:
X is larger than AED 40
X is equal to or smaller than AED 40.
If X is more than AED 40, then we have a game that costed more than AED 40.
If X is less than or equal to AED 40, then:
X ≥ AED 40
Now let's take the maximum value of X in this scenario, this is:
X = AED 40
Replacing this in the first inequality, we get:
X + Y > AED 80
Replacing the value of X we get:
AED 40 + Y > AED 80
Y > AED 80 - AED 40
Y > AED 40
So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.
So we proven that in all the possible cases, at least one of the two games costs more than AED 40.
