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lbvjy [14]
3 years ago
10

Carol is going to make a wooden pyramid and then paint it. She drew the net of a square pyramid as shown below to help her plan

the project. What should be the total surface area in square feet of Carol's pyramid?
1. 15.0
2. 21.0
3. 24.0

Mathematics
1 answer:
rodikova [14]3 years ago
3 0

The given pyramid's total surface area is 3. 24.0 square feet.

Step-by-step explanation:

Step 1:

To calculate the surface area of the given figure, we need to find the surface areas of the different shapes in the figure.

There are 3 triangles and 1 square in the figure.

Step 2:

All the triangles are similar.

The surface area of a triangle = \frac{1}{2} (baselength)(height).

The similar triangles have a base length of 3 feet and a height of 2.5 feet.

The surface area of 1 similar triangle = \frac{1}{2} (3)(2.5)= 3.75 square feet.

The surface area for all the similar triangles = 3.75 (4) = 15 square feet.

Step 3:

The surface area of a square is the square of its side length. The square has a side length of 3 feet.

The surface area of the square = a^{2} = 3^{2} =9 square feet.

Step 4:

To calculate the total surface area we sum up all the individual surface area.

The total surface area = 15 + 9 = 24 square feet which is the third option.

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LenaWriter [7]

Answer:

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Step-by-step explanation:

Lets solve this step by step,

First we insert 8 in x's place:

(8 - 4) + 12

Now we solve:

8 - 4 = 4

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4 + 12 = 16

Answer: 16

Hope this Helps

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3 years ago
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koban [17]

Answer:

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Step-by-step explanation:

Step 1: find the sum of all numbers

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Step 2: divide by how many values there are

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Step 3: solve

104.65 ÷ 8 = 13.08125....

Step 4: round to the hundredths place

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3 years ago
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How many ways can you distribute $4$ identical balls among $4$ identical boxes?
Harman [31]

Answer:

5 ways

Step-by-step explanation:

We have to name the cases.

1. 4 - 0 - 0 - 0

2. 3 - 1 - 0 - 0

3. 2 - 2 - 0 - 0

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5. 1 - 1 - 1 - 1

We don't name 0 - 0 - 1 - 3 or 0 - 1 - 1 - 2 etc. because it is the same thing.

4 0
3 years ago
Use series to verify that<br><br> <img src="https://tex.z-dn.net/?f=y%3De%5E%7Bx%7D" id="TexFormula1" title="y=e^{x}" alt="y=e^{
SVETLANKA909090 [29]

y = e^x\\\\\displaystyle y = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y= 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \frac{d}{dx}\left( 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\frac{x^4}{4!}+\ldots\right)\\\\

\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\

This shows that y' = y is true when y = e^x

-----------------------

  • Note 1: A more general solution is y = Ce^x for some constant C.
  • Note 2: It might be tempting to say the general solution is y = e^x+C, but that is not the case because y = e^x+C \to y' = e^x+0 = e^x and we can see that y' = y would only be true for C = 0, so that is why y = e^x+C does not work.
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alukav5142 [94]

Answer:

it's B

Step-by-step explanation:

just solve them and they match

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3 years ago
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