Please need help on this

Mathematics

1 answer:

Artyom0805 [142]3 years ago

4 0

roberta saves $10 a week

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How do you solve 5 3/4 divided by 4 and show step by step

igomit [66]

There are various ways in which to do this problem. I'd suggest
converting 5 3/4 into an improper fraction and then dividing that improper fraction by 4:

20+3 23 1 23
------- divided by 4 is --------- * ----- = ------ (answer)
4 4 4 16

5 0

3 years ago

How many solution does this equation have

eimsori [14]

The equation has 1 solution

4 0

3 years ago

Read 2 more answers

Can anyone help me please

kicyunya [14]

Answer:

yes wait im doing it. do I put them un order

3 0

3 years ago

For the statement? below, write the claim as a mathematical statement. State the null and alternative hypotheses and identify wh

snow_tiger [21]

Answer:

Option E - sigma greater than or equal to $327

Step-by-step explanation:

In this question, we are testing whether the standard deviation of the base price of a certain type of all-terrain vehicle is at least $327.

Now, standard deviation is denoted by the symbol sigma(σ). Since the test is saying it should be at least $327, it means it should either be equal to $327 or greater than $327.

Thus, we would use the symbol ≥ which means "greater than or equal to".

Thus, the claim as a mathematical statement would be;

sigma greater than or equal to $327

5 0

3 years ago

Find the hypotenuse of each isosceles right triangle when the legs are of the given measure. 6 sqrt 2

Gemiola [76]

Isosceles right triangles have two equal sides (a and b) that are not the hypotenuse (c). And when two sides are equal, so are their opposite angles. There are only 180° degrees in any triangles, thus the right angle = 90°, so 90 left for the two equal, means that 2x=90,
x = 45°.

There are several ways to go about solving a triangle like this. The best and easiest is simply to memorize that the hypotenuse is exactly root2 times the other sides. Or, each isosceles side is the hypotenuse (c) ÷ root2
$a = b = c \div \sqrt{2} \\ c = a\sqrt{2} \\ c = 6 \sqrt{2} \times \sqrt{2} = 6 \times 2 = 12$
Another way to do it is the longer proof of Pythagorean Theorem:
${c}^{2} = {a}^{2} + {b}^{2}... \: \: c = \sqrt{({a}^{2} + {b}^{2})} \\$
$c= \sqrt{({6 \sqrt{2}) }^{2} + ({6 \sqrt{2})}^{2}} \\ = \sqrt{(2 \times{(6 \sqrt{2} )}^{2} )} = \sqrt{2(36 \times 2)} \\ c = \sqrt{144} = 12$

7 0

3 years ago