Solve by using <span>Quadratic Formula
</span>
In this case,
![a=16](https://tex.z-dn.net/?f=a%3D16)
<span>,</span>
![b=-32](https://tex.z-dn.net/?f=%20b%3D-32)
<span> and </span>
![c=25{y}^{2}-159](https://tex.z-dn.net/?f=c%3D25%7By%7D%5E%7B2%7D-159)
<span>
</span>
![x= \dfrac{32+ \sqrt{(32)^2-4*16(25y^2-159)} }{2*16} ,}](https://tex.z-dn.net/?f=x%3D%20%5Cdfrac%7B32%2B%20%5Csqrt%7B%2832%29%5E2-4%2A16%2825y%5E2-159%29%7D%20%7D%7B2%2A16%7D%20%2C%7D)
<span>
</span>
<span>
</span>
![x=1+ \dfrac{5i \sqrt{y^2-7} }{4} ,1- \dfrac{5i \sqrt{y^2-7} }{4}](https://tex.z-dn.net/?f=x%3D1%2B%20%5Cdfrac%7B5i%20%5Csqrt%7By%5E2-7%7D%20%7D%7B4%7D%20%2C1-%20%5Cdfrac%7B5i%20%5Csqrt%7By%5E2-7%7D%20%7D%7B4%7D%20)
<span>
</span>
8 4
14 7
6 3
That is the answer for the table
Use bodmas/pemdas rule
4^3*(4)-5^0
64*4-1 anything to the power zero is one
256-1
255
<span>0.25 divided by 0.02 is 12.5
</span>
Answer:
498,173.26.
Step-by-step explanation:
The place value of 9 in the number 3, 29,513 = 9000
In the required number,
Place value of 9 is 10 times of the value of 9 in 329, 513 = 9000 * 10 = 90,000
The value of 2 is one-tenth of 2 in 7562 = 2/10 = 0.2
The value of 6 is one-tenth value of 6 in 4.68 = 0.60/10 = 0.06
Thus, the required number would be 498,173.26 as the other numbers do not justify the above conditions of having 9 at ten thousand place, 2 at tenth, and 6 in hundredth place.