Please need help on this

Keisha is riding her bike on Bayview Bike path. Keisha‘s bike got a flat tire 2/3 of the way down the path, so she had to stop.

Leona [35]

Answer:

$\frac{7}{12}$ miles.

Step-by-step explanation:

Please consider the complete question.

Bay View Bike Path is 7/8 miles. Keisha is riding her bike on Bay View bike path. Keisha's bike got a flat tire 2/3 of the way down the oath and she had to stop. How far did Keisha ride?

To find the distance covered by Keisha while riding the bike, we need to find 2/3 of 7/8 miles.

$\text{Distance that Keisha ride}=\frac{2}{3}\times \frac{7}{8}$

$\text{Distance that Keisha ride}=\frac{1}{3}\times \frac{7}{4}$

$\text{Distance that Keisha ride}=\frac{1\times 7}{3\times 4}$

$\text{Distance that Keisha ride}=\frac{7}{12}$

Therefore, Keisha ride $\frac{7}{12}$ miles.

3 0

3 years ago

Can someone match all of these definitions to all five words for me? I’m very confused but I’ll mark brainlist if you do at leas

forsale [732]

Solution: Any value for a variable that makes the equation true.

Reciprocal: Focuses on the use of multiplication and division

Coefficient: A number that is multiplied by a variable in an algebraic expression is a coefficient

Term: A term of an algebraic expression is a number, variable, or product of numbers and variables

Base: The base of a power is the factor that is multiplied repeatedly in the power.

Hope this helps, and have a great day!

5 0

3 years ago

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Henry has a faulty watch. It is losing minutes every day. How many minutes will be lost after 7 days?

Ann [662]

A I think this is the answer but I’m not sure

6 0

3 years ago

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Find the slope-intercept form of the equation of the line passing through the given points.

Ugo [173]

$The\ slope-intercept\ form:y=mx+b\\\\The\ slope-point\ form:y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

$(1;\ 1)\to x_1=1;\ y_1=1\\\left(3;-\dfrac{1}{5}\right)\to x_2=3;\ y_2=-\dfrac{1}{5}.\\\\Subtitute:\\\\m=\dfrac{-\frac{1}{5}-1}{3-1}=\dfrac{-1\frac{1}{5}}{2}=-\dfrac{\frac{6}{5}}{2}=-\dfrac{\not6^3}{5}\cdot\dfrac{1}{\not2_1}=-\dfrac{3}{5}$

$y-1=-\dfrac{3}{5}\left(x-1\right)\\\\y-1=-\dfrac{3}{5}x+\dfrac{3}{5}\ \ \ \ |add\ 1\ to\ both\ sides\\\\\boxed{y=-\frac{3}{5}x+1\frac{3}{5}}$

5 0

4 years ago

The final grade in a biology course is determined by a score from 0 to 100, which has three components; a laboratory component o

vovangra [49]

Answer:

75*25%+(38+40)*50%+85*25%=59.5

Step-by-step explanation:

7 0

3 years ago