Answer:
(3x - 3)(x + 2)
Step-by-step explanation:
3x^2 + 3x - 6
(3x^2 + 6x)(-3x - 6)
3x(x + 2) -3(x + 2)
(3x - 3)(x + 2)
Answer:
A.) Even.
Step-by-step explanation:
If a function is an even function, then
F(-x) = f(x)
Also, if a function is an odd function, then, f(-x) = -f(x)
You are given the below function
f(x) = 1 + 3x^2 − x^4
Let x = 2
Substitute 2 for x in the function
F(x) = 1 + 3(2)^2 - (2)^4
F(x) = 1 + 3(4) - 16
F(x) = 1 + 12 - 16
F(x) = -3
Also, Substitute -2 for x in the function
F(x) = 1 + 3(-2)^2 - (-2)^4
F(x) = 1 + 3(4) - 16
F(x) = 1 + 12 - 16
F(x) = -3
Since f(-x) = f(x), we can conclude that
F(x) = 1 + 3x^2 - x^4 is even
Answer:
∠1 ≅ ∠2 ⇒ proved down
Step-by-step explanation:
#12
In the given figure
∵ LJ // WK
∵ LP is a transversal
∵ ∠1 and ∠KWP are corresponding angles
∵ The corresponding angles are equal in measures
∴ m∠1 = m∠KWP
∴ ∠1 ≅ ∠KWP ⇒ (1)
∵ WK // AP
∵ WP is a transversal
∵ ∠KWP and ∠WPA are interior alternate angles
∵ The interior alternate angles are equal in measures
∴ m∠KWP = m∠WPA
∴ ∠KWP ≅ ∠WPA ⇒ (2)
→ From (1) and (2)
∵ ∠1 and ∠WPA are congruent to ∠KWP
∴ ∠1 and ∠WPA are congruent
∴ ∠1 ≅ ∠WPA ⇒ (3)
∵ WP // AG
∵ AP is a transversal
∵ ∠WPA and ∠2 are interior alternate angles
∵ The interior alternate angles are equal in measures
∴ m∠WPA = m∠2
∴ ∠WPA ≅ ∠2 ⇒ (4)
→ From (3) and (4)
∵ ∠1 and ∠2 are congruent to ∠WPA
∴ ∠1 and ∠2 are congruent
∴ ∠1 ≅ ∠2 ⇒ proved
Answer:
14
Step-by-step explanation:
3 diangonalss joined togeheter is call a symertry
Rise/Run=2/4= 1/2, the answer would be 1/2.
