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2 years ago

What is the value of |4.75|

1 answer:

4 0

Answer:

The absolute value of 4.75 is 4.75. It can’t be a negative, only a positive. On the off chance you’re looking for other alternate forms of 4.75, they would be either 19/4 or 4 3/4.

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Write the equation in standard form<br><br> y = -10x + 6

Mumz [18]

Step (1) Flip the equation

−10x+6=y

Step (2) Add -6 to both sides

−10x+6+−6=y+−6

−10x=y−6

Step (3) Divide both sides by -10

−10x−10=y−6−10

ANSWER
$x = \frac{ - 1}{10} y + \frac{3}{5}$

5 0

2 years ago

49 is 35% of what number?

NNADVOKAT [17]

We write this like this:

49=35%x

and we want to find the x.

let's invert the sides:

35%x=49.

35 is equal to 0.35

0.35*x=49

and now we only divide both sides by 0.35:

x=140

so the answer is 140.

(aternatively we can do it through fractions:

35/100*x=49
divide both sides by 7:

5/100*x=7

simplify the first fraction
1/20*x=7

and multiply by 20:

x=140

4 0

2 years ago

4. In this figure, B↔A↔

LenaWriter [7]

Answer:

B. 25 degrees

Step-by-step explanation:

i think

6 0

3 years ago

Suppose a batch of metal shafts produced in a manufacturing company have a standard deviation of 1.5 and a mean diameter of 205

Crank

Answer:

$P(205-0.3=204.7$

$z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778$

$z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778$

So we can find this probability:

$P(-1.778$

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

$P = 1-0.9243 = 0.0757$

Step-by-step explanation:

Let X the random variable that represent the diamters of interest for this case, and for this case we know the following info

Where $\mu=205$ and $\sigma=1.5$

We can begin finding this probability this probability

$P(205-0.3=204.7$

For this case they select a sample of n=79>30, so then we have enough evidence to use the central limit theorem and the distirbution for the sample mean can be approximated with:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}$

And we can find the z scores for each limit and we got:

$z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778$

$z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778$

So we can find this probability:

$P(-1.778$

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

$P = 1-0.9243 = 0.0757$

6 0

2 years ago

Write an algebraic expression for this situation . Steve made a down payment of $300 on a new tv. He paid $37 per month for x mo

Temka [501]

300+37x
300+37(9)
300+333
633

5 0

3 years ago