Answer:
Percent error = -4.02 (Approx.)
Step-by-step explanation:
Given:
Estimated pool dimension = 15 ft long and 35 ft wide
Actual pool dimension = 14.5 ft long and 34.75 ft wide
Find:
Percent error
Computation:
Area of Estimated pool = 15 x 35
Area of Estimated pool = 525 ft²
Area of Actual pool = 14.5 x 34.75
Area of Actual pool = 508.875 ft²
Percent error = [(Actual - Estimated) / Estimated]100
Percent error = [(508.875 - 525) / 525]100
Percent error = [(-21.125) / 525]100
Percent error = -4.02 (Approx.)
Answer:
#3.) The initial value of 16 gal at x = 5 minutes means that 16 gallons of water was present 5 minutes after the barrel started leaking.
#4.) Find how many minutes until the barrel is empty of water.
Let y = 0, to solve for time x.
0 = (-2/5)*x + 18
(2/5)*x = 18
x = (5/2)* 18 = 5*9 = 45 minutes
Up to and after 45 minutes, the barrel is empty of water.
Step-by-step explanation:
#2.)
minutes: 5, 10, 15, 20
water(gal): 16, 14, 12, 10
Find slope: slope m = (14 - 16)/(10 - 5) = -2/5
y - 10 = (-2/5)*(x - 20)
y - 10 = (-2/5)* x + 8
y = (-2/5)*x + 18
rate of change slope means that for every minute 2/5 gallons of water is lost
#3.) The initial value of 16 gal at x = 5 minutes means that 16 gallons of water was present 5 minutes after the barrel started leaking.
#4.) Find how many minutes until the barrel is empty of water.
Let y = 0, to solve for time x.
0 = (-2/5)*x + 18
(2/5)*x = 18
x = (5/2)* 18 = 5*9 = 45 minutes
Answer:(2,-9)
Step-by-step explanation:
