Hi,
Essentially, we are saying that Alyssa gets 5 parts of the whole thing (140,000), Bart gets 3 parts of the whole and Meghan gets 2 parts of the whole. The sum total of their parts = the whole. So now we need to find out how much one part is. Thus,"one part" should be the variable. Substitute p for "one part", so Alyssa gets 5p, Bart gets 3p, and Meghan gets 2p. Since the sum of the parts = the whole, your problem sets up as: 5p + 3p + 2p = 140,000 --> 10p = 140,000 --> 10p/10 = 140,000/10 --> x = 14,000.
Alyssa gets 5p or (5 x 14,000)
Bart gets 3p or (3 x 14,000)
Meghan gets 2p or (2 x 14,000)
If the whole was a loss, it would be a negative, and instead of getting money, they would lose money.
Several examples of side lengths that are Pythagorean triples are the following with the corresponding side lengths A, B, C:
(5, 12, 13), (7, 24, 25), (3, 4, 5)
-E :)
Answer:
-2/3
Step-by-step explanation:
in y=mx+b, m= the slope
and if you were graphing, you would put 2 on the y axis and use the rise over run strategy for the slope
hope this helped:)
Check the picture.
let the length of a side of each of the squares removed be x.
The box formed will have dimensions: 80-2x, 50-2x, x(the height)
So the volume can be expressed as a function of x as follows:
f(x)=(80-2x)(50-2x)x=
![[4000-160x-100x+4 x^{2} ]x=(4 x^{2}-260x+4000)x](https://tex.z-dn.net/?f=%5B4000-160x-100x%2B4%20x%5E%7B2%7D%20%5Dx%3D%284%20x%5E%7B2%7D-260x%2B4000%29x)
so

the solutions of f'(x)=0 gives the inflection points, so the candidates for maxima points,

solving the quadratic equation, either by a calculator, graphing software, or by other algebraic methods as the discriminant formula, we find the solutions
x=10 and x=33.333
plug in f(x) these values to see which greater:

cm cubed

which is negative because (50-66.666)<0
Answer: 18000 cm cubed