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wlad13 [49]
3 years ago
14

How are graphs and equations related

Mathematics
2 answers:
Katarina [22]3 years ago
8 0

Answer:

i no see pic

Step-by-step explanation:

MrRa [10]3 years ago
3 0

Answer:

The equation makes the graph, and vise versa.

Step-by-step explanation:

A linear equation in two variables describes a relationship in which the value of one of the variables depends on the value of the other variable. In a linear equation in x and y, x is called x is the independent variable and y depends on it. ... You can then plot the points named by each (x,y) pair on a coordinate grid.

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Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
Write an equation through the line point (-2,5) with slope 4
dybincka [34]

Answer:

Step-by-step explanation:

6 0
3 years ago
Is 12n2+12n+1 prime over the set of polynomials with rational coefficients? Need help ASAP
professor190 [17]

Answer:

No, the given polynomial is not prime.

Step-by-step explanation:

Given: a polynomial 12n^2+12n+1

To check: whether the given polynomial is prime or not.

Solution:

A prime polynomial is a polynomial that cannot be factored into polynomials of lower degree and has integers as coefficients.

In the given polynomial, coefficients are integers.

Also, the polynomial 12n^2+12n+1 cannot be factored further into polynomials of lower degree.

So, the given polynomial is not prime.

8 0
4 years ago
I need help thank you
Svetllana [295]

Answer:

there is no question lol but i am here to help anyway

Step-by-step explanation:

3 0
3 years ago
Question 9 (Essay Worth 10 points) (03.06 HC) Seth is using the figure shown below to prove Pythagorean Theorem using triangle s
mario62 [17]

In the case above, the length of Angle DA is 6 and angle ABD ≈ Angle CAD.

<h3>What is the angle about?</h3>

Note that:

Δ ABC , A = 90

To find length of DA :

Let Δ ACB = x

So Δ ABC = 90 -x

For Δ ABC and ADC:

Δ ADB = Δ ADC  (90°)

Δ ABD = Δ DAC (90 - x)

For Δ ABC ≈  ADC:

\frac{AD}{DC} = \frac{BD}{AD}

AD² = BD. CD.

AD²= 9 . 4

AD²= 36

AD = 6

Therefore, In the case above, the length of Angle DA is 6 and angle ABD ≈ Angle CAD.

Learn more about triangle  from

brainly.com/question/17335144

#SPJ1

4 0
2 years ago
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