The zeros and intercepts of the polynomial m^2 + 5m + 4 will be different.
<h3>Intercepts and zero of a function</h3>
A quadratic function is a function that has a degree of 2.
Given the following equation
f(m) = m^2 + 5m + 4
The x-intercept occurs at the point where f(m) is zero and same is applicable to the zeros of the function.
This shows that the zeros and intercepts of the polynomial m^2 + 5m + 4 will be different.
Learn more on intercepts here: brainly.com/question/1884491
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The factors of 3x^2+10x+3 are (3x+1)(x+3)
Answer:
k > 12
Step-by-step explanation:
If a quadratic equation has no real roots the values of b^2 - 4ac
( for the general form ax^2 + bx + c = 0) is negative,
So we have the inequality:
(-12)^2 - 4*3* k < 0
144 - 12k < 0
12k > 144
k > 12
Answer:
C. (6, 5) and (3, -4)
Step-by-step explanation:
Given the equation 3x - y = 13, we need to figure out which points satisfy it. In order for an ordered pair to satisfy an equation, when we plug the x-coordinate in for x and the y-coordinate in for y, the equation should hold true.
Let's try with (6, 5):
3x - y = 13
3 * 6 - 5 =? 13
18 - 5 =? 13
13 = 13
Since this is true, we know that (6, 5) is indeed a solution.
Now let's try with (3, -4):
3x - y = 13
3 * (3) - (-4) =? 13
9 + 4 =?13
13 = 13
Again, since this is true, then (3, -4) must be a solution.
Thus, the answer is C.
<em>~ an aesthetics lover</em>