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mestny [16]
3 years ago
9

Whats the answer to 2c + 9 = 27

Mathematics
2 answers:
Inessa05 [86]3 years ago
7 0

Ans

c=9

Step-by-step explanation:

2 x 9 = 18 +9 = 27

disa [49]3 years ago
3 0
The answer to the question is 2(9)+9=27 I hope this helps!
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A container holds 50 electronic components, of which 10 are defective. if 6 components are drawn at random from the container, t
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Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Problem 1</u>

We know that there's a probability of p=\frac{40}{50}=\frac{4}{5}=0.8 of choosing an electronic component that is not defective and a probability of q=\frac{10}{50}=\frac{1}{5}=0.2 of choosing an electronic component that is defective:

\displaystyle P(X\geq4)=P(X=4)+P(X=5)+P(X=6)\\\\P(X\geq4)=\binom{6}{4}(0.8)^4(1-0.8)^{6-4}+\binom{6}{5}(0.8)^5(1-0.8)^{6-5}+\binom{6}{6}(0.8)^6(1-0.8)^{6-6}\\\\P(X\geq4)=\frac{6!}{4!(6-4)!}(0.8)^4(0.2)^2+\frac{6!}{5!(6-5)!}(0.8)^5(0.2)^1+\frac{6!}{6!(6-6)!}(0.8)^6(0.2)^0\\ \\P(X\geq4)=0.90112

So, if 6 components are drawn at random from the container, the probability that at least 4 are not defective is 0.90112

<u>Problem 2</u>

<u />\displaystyle P(X=3)=\binom{8}{3}(0.2)^3(1-0.2)^{8-3}\\\\P(X=3)=\frac{8!}{3!(8-3)!}(0.2)^3(0.8)^5\\ \\P(X=3)\approx0.1468

So, if 8 components are drawn at random from the container, the probability that exactly 3 are defective is 0.1468

6 0
2 years ago
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