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kogti [31]
3 years ago
11

Expand $\left(x^2 \frac{1}{x}\right)^3$. (Write the terms with higher degree first, so for example an $x^2$ term would come befo

re $x$ or $\frac{1}{x}$.)
Mathematics
1 answer:
Ilya [14]3 years ago
4 0

Answer:

x^6+3x^3+3+\dfrac{1}{x^3}

Step-by-step explanation:

We can use the pascal triangle to find the coefficients of the expasion of the cube. It holds that

(x^2 + \dfrac{1}{x})^3=(x^2)^3+3(x^2)^2\dfrac{1}{x}+3x^2(\dfrac{1}{x})^2+(\dfrac{1}{x})^3\\\\=x^6+3x^4\dfrac{1}{x}+3x^2\dfrac{1}{x^2}+\dfrac{1}{x^3}\\\\=x^6+3x^3+3+\dfrac{1}{x^3}

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