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Lady bird [3.3K]
2 years ago
9

Yall someone help I still have a bunch if other test and I'm so tired ;-;

Mathematics
1 answer:
g100num [7]2 years ago
6 0

Me das mas información?

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Solve the equation -20=-4x-6x​
asambeis [7]

Answer: x = 2

Step-by-step explanation:

First you add -4x and -6x to get -10x. Then you will have -20 = -10x. So you divide both sides by -10 to get 2 = x

8 0
3 years ago
Jake walks from the library to the museum along 3th avenue. he stops at the post office and at a store. The distances between th
alexdok [17]
I believe the answer would be 4/6 which would simplify to 2/3
4 0
3 years ago
What is the surface area of a rectangular prism with a length of 3 mm, a width of 5 mm, and a height of 8 mm?
kherson [118]
158, because to solve this question we first need to know the formula for finding the surface area of a rectangular prism which is A=<span>2<span>(<span><span><span>wl</span>+<span>hl</span></span>+<span>hw</span></span><span>) then you just need to input the numbers like so A=2(5*3+8*3+8*5) then when you simplify this down you get A=2(79) then distribute like so so A=158

Enjoy!=)</span></span></span>
8 0
2 years ago
1. Question: What is the number of the parking space covered by the car?
GalinKa [24]

Answer: the number of the parking space covered by the car is 87

Step-by-step explanation:

Numbers are assigned to each parking spot. Looking closely at the numbers assigned to each spot, the numbers are inverted and the number on each successive spot differ by one. The numbers are 86, 87, 88, 89, 90, 91

Therefore, the number assigned to the spot where the car would be 87

4 0
3 years ago
Integrate ​G(x,y,z)equalsz over the parabolic cylinder yequalszsquared​, 0less than or equalsxless than or equals2​, 0less than
yKpoI14uk [10]

I gather you're supposed to compute the integral of G(x,y,z)=z over a surface S that is the part of the parabolic cylinder y=z^2 with 0\le x\le2 and 0\le z\le\frac{\sqrt{15}}2.

We can parameterize S by

\vec s(x,z)=x\,\vec\imath+z^2\,\vec\jmath+z\,\vec k

with the given constraints on x and z. Take the normal vector to S to be

\vec s_x\times\vec s_z=-\vec\jmath+2z\,\vec k

so that the surface element is

\mathrm dS=\|\vec s_x\times\vec s_z\|\,\mathrm dx\,\mathrm dz=\sqrt{1+4z^2}\,\mathrm dx\,\mathrm dz

Then in the integral, we have

\displaystyle\iint_Sz\,\mathrm dS=\int_0^2\int_0^{\sqrt{15}/2}z\sqrt{1+4z^2}\,\mathrm dz\,\mathrm dx=\boxed{\frac{21}2}

5 0
3 years ago
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