The scalar product can be described as the magnitude of B times the component of A that is parallel to B. In terms of the positi
ve scalar quantities a, b, and d, what is the component of A that is parallel to B? Suppose that c = 0.
1 answer:
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(6, 2 )
substitute x = 5 into the equation and solve for y
6y + 8 = 20 ( subtract 8 from both sides )
6y = 12 ( divide both sides by 6 )
y = = 2
the ordered pair is (5, 2 )
