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3 years ago

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The scalar product can be described as the magnitude of B times the component of A that is parallel to B. In terms of the positi

ve scalar quantities a, b, and d, what is the component of A that is parallel to B? Suppose that c = 0.

1 answer:

Mice21 [21]3 years ago

4 0

Answer:

See it in the pic.

Step-by-step explanation:

See it in the pic.

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riadik2000 [5.3K]

Answer:

The answer is 75 degrees.

Step-by-step explanation:

The explanation is that the the supplementary angle to 80 is 100 since a straight line has an angle of 180, now the 100 degree angle is congruent to the angle x + 25 which means that x + 25 is equal to 100 so x is 75

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3 years ago

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yan [13]

Answer:

1. Pyramid= ll+l^2 2. Rectangular prism= 2 lw+2lh+2wh 3. Cylinder= 2pi pi rh+2pi pi r^2 4.Triangular Prism= 2 B + Ph 5. Cone= Pi rl+ pi r^2

Step-by-step explanation:

Pretty sure this is your answer. Hope it helps!

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2 years ago

big water canoeing company rents conoes for 75$ per hour. explain why the point (0,0) and (1, 75) are on the graph of the relati

Pepsi [2]

The X (1) axis represents the number of hours, and the Y (75) axis represents the number of dollars. When 0 hours are passed, 0 hours are payed (0,0) 1 hour 75 dollars are payed (1, 75) 2 hours 150 dollars is payed (2, 150) and so on

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3 years ago

Compare each set of rational numbers.

Fed [463]

Hey.. don’t click on that link or any links on here !!! but i jus wanna say you didn’t attach an image of your question :).

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3 years ago

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

So

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

So

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago