Answer:
I think I explained the circle one before so I'll explain the left question because I wanted some points.
here,
area of circle is πr² which is given= 12 π cm²
so πr²= 12π
r= 2√3
d= 2r= 4√3
AB is diameter so AB= 4√3
Answer:
ASA
ΔFGH ≅ ΔIHG ⇒ answer B
Step-by-step explanation:
* Lets revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and
including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ
≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles
and one side in the 2ndΔ
- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse
leg of the 2nd right angle Δ
* Lets prove the two triangles FGH and IHG are congruent by on of
the cases above
∵ FG // HI and GH is transversal
∴ m∠FGH = m∠IHG ⇒ alternate angles
- In the two triangles FGH and IHG
∵ m∠FHG = m∠IGH ⇒ given
∵ m∠FGH = m∠IHG ⇒ proved
∵ GH = HG ⇒ common side
∴ ΔFGH ≅ ΔIHG ⇒ ASA
* ASA
ΔFGH ≅ ΔIHG
The answer is x=-2
As you could see, this is a factored function.
The un-factored version is x^2+4x-12
-b/2a=x
-4/2=-2= x of vertex
Answer: 96 adult tickets were sold.
Step-by-step explanation:
Let x represent the number of adult tickets that were sold.
Let y represent the number of students tickets that were sold.
For the last basketball game, 381 tickets were sold. This means that
x + y = 381
Adult tickets sold for $7, and student tickets sold for $3. If the ticket sales totaled 1,527, it means that
7x + 3y = 1527 - - - - - - - - - - - -1
Substituting x = 381 - y into equation 1, it becomes
7(381 - y) + 3y = 1527
2667 - 7y + 3y = 1527
- 7y + 3y = 1527 - 2667
- 4y = - 1140
y = - 1140/- 4
y = 285
x = 381 - y = 381 - 285
x = 96
Answer: maximum height of the football = 176 feet
Step-by-step explanation:
We want to determine the maximum height of the football from the ground. From the function given,
h(t) = -16t^2+96t +32, it is a quadratic function. Plotting graph if h will result to a parabolic shape. The maximum height of the football = the vertex of the parabola. This vertex is located at time, t
t = -b/2a
b = 96 and a= -16
t = -b/2a = -96/2×-16= 3
Substituting t = 3 into the function if h
h(t) = -16×3^2+96×3 +32
=-16×9 + 96×3 +32
= -144+ 288+32
=176 feet
