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Alenkasestr [34]
2 years ago
7

A rectangular prism has volume 5,760 cubic meters, length 8 meters, and width 36 meters. Find its height, in meters.

Mathematics
1 answer:
USPshnik [31]2 years ago
5 0

Answer:

h=20 m

Step-by-step explanation:

Just divide 5,760 by 8 then by 36 for the answer

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Given: The coordinates of isosceles trapezoid JKLM are J(-b, c), K(b, c), L(a, 0), and M(-a, 0). Prove: The diagonals of an isos
In-s [12.5K]
We have to find the lengths of the diagonals KM and JL:
d ( KM ) = √ (( - a - b )² + ( 0 - c )²) = √ (( a + b )² + c² )
d ( JL ) = √ ( ( a - ( - b ) )² + ( 0 - c )²) = √ ( ( a + b )² + c² )
So the lengths of the diagonals KM and JL are congruent.
The lengths of the diagonals of the isosceles trapezoid are congruent.   
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3 years ago
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A vector is in standard position, with its terminal point in the second quadrant and an x-coordinate of -5. The vector
Nonamiya [84]

Answer:6.0, 130

Step-by-step explanation:

Just got the question right on edgenuity.

3 0
3 years ago
In the diagram below,
sergey [27]
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5 0
2 years ago
leonhard wants to place a triangular-based cabinet in the corner of his rectangle-shaped living room. the triangular base has a
Georgia [21]
The answer is x =  \frac{-7+ \sqrt{193} }{4}.

There is very similar question on Brainly, in which dimensions of the living room are given (20 feet, 30 feet).
So, knowing this, we first need to calculate how much 6% of the living room is.
The area of the living room is 600 square feet, since it is rectangle-shaped:
P = a * b = 200 feet * 30 feet = 600 square feet.

6% of 600 square feet is 36 square feet:
600 square feet : 100% = A : 6%
A = 600 * 6 / 100 = 36 square feet

The area of the triangular-based cabinet (A) is A = \frac{a*h}{2}, where a is the base, and h is the height of the triangle.
It is given:
A = 36
a = 2x + 3
h = 3x + 6

Now, let's implement this to the formula A =  \frac{a*h}{2}:
36 =  \frac{(2x+3)(3x+6)}{2}
⇒ 36*2=6 x^{2} +12x+9x+18
72=6 x^{2} +21x+18

Let's both sides divide by 3:
24=2 x^{2} +7x+6
⇒ 2 x^{2} +7x-18=0

This is the quadratic formula (a x^{2} +bx+c=0) for which
x =  \frac{-b+\sqrt{b^{2} -4ac} }{2a} or
<span>x = \frac{-b-\sqrt{b^{2} -4ac} }{2a}.
</span>We will use only <span>x = \frac{-b+\sqrt{b^{2} -4ac} }{2a}, because the length cannot have negative value.</span>


<span>From the equation 2 x^{2} +7x-18=0, we know that
</span>a = 2
b = 7
c = -18

Thus, <span> x = \frac{-7+ \sqrt{193} }{4}:
</span>x= \frac{-b+ \sqrt{ b^{2} -4ac} }{2a} = \frac{-7+ \sqrt{ (7)^{2} -4*2*(-18)} }{2*2} = \frac{-7+ \sqrt{49+144} }{4} = \frac{-7+ \sqrt{193} }{4}

4 0
3 years ago
Jose Canseco hit three fifth-deck home runs at SkyDome/Rogers Centre during his career, including the first ever at the stadium
Mademuasel [1]

Answer:

187 ft/s

Step-by-step explanation:

Given in the y direction:

v₀ = 0 ft/s

Δy = 75 ft

a = 32 ft/s²

Find: t

Δy = v₀ t + ½ at²

(75 ft) = (0 ft/s) t + ½ (32 ft/s²) t²

t = 2.165 s

Given in the x direction:

Δx = 480 ft

a = 0 ft/s²

t = 2.165 s

Find: v₀

Δx = v₀ t + ½ at²

(480 ft) = v₀ (2.165 s) + ½ (32 ft/s²) (2.165 s)²

v₀ = 187 ft/s

4 0
3 years ago
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