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deff fn [24]
3 years ago
13

Find the value of x if B is the midpoint of AC, AB = 2x + 9 and BC = 37.

Mathematics
2 answers:
xxTIMURxx [149]3 years ago
6 0
The answer would be 14 x=14
Leno4ka [110]3 years ago
5 0

Answer:

14

Step-by-step explanation:

B is the midpoint of AC, in other words it is the halfway point.

So A to B should be equal to B to C

Our expression is:

2x + 9 = 37

Subtract 9

2x = 28

Divide by 2

x = 14

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Drag and drop the numbers into the boxes to create an expression that is equivalent to the given expression. b+b+b+b+4c−2b−c
Marat540 [252]

Answer:

I know this is late, but for<em> future people</em>:

I believe the answer is <u>2b+3c</u>.

Step-by-step explanation:

I'm pretty sure all you have to do is combine like terms.

I'm also taking the test at the moment.

3 0
3 years ago
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There are two red jars of marbles and one blue jar of marbles jars of a certain color have the same number of marbles in them. T
satela [25.4K]
We can set up an equation to solve this problem.  I am setting the number of marbles in a red jar to R.

R + R + R - 16 = 41

We solve this by adding 16 to both sides and combining all of the R terms..  This gives us:

3R = 57

We can finish this problem by dividing both sides by 3.

R = 19.  So, there are 19 marbles in a red jar.

We can easily figure out how many marbles are in a blue jar by subtracting the total amount of marbles in 2 red jars from the total amount of marbles.  I am setting the amount of marbles in a blue jar to B.

41 - 19*2 = B

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So, there are 3 marbles in a blue jar and 19 marbles in a red jar.



7 0
3 years ago
Find the measures of the following angles.
makvit [3.9K]

Answer:

1: 36° 2: 122° 3: 122° 4: 38°

Step-by-step explanation:

First start out by getting 2 and 3. so 58+angle 3 has to sum to 180° since they are supplementary and are a straight line. So 180-58=122. Angle 2 is the same since theyre vertical. then since a triangle has 180° total, you subtract from 180 to find the final angle measurement.

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Find x<br><br><br><br><br> Thanks for the help in advance!
Marina86 [1]

I'm not sure if this is the easiest way of doing this, but it surely work.

Let the base of the triangle be AB, and let CH be the height. Just for reference, we have

AH=2,\quad HB=6,\quad AC=x

Moreover, let CH=y and BC=z

Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system

\begin{cases}4+y^2=x^2\\36+y^2=z^2\\x^2+z^2=64\end{cases}

If we solve the first two equations for y squared, we have

y^2=x^2-4\\y^2=z^2-36

And we can deduce

z^2 = x^2+32

So that the third equation becomes

x^2+x^2+32=64 \iff 2x^2 = 32 \iff x^2=16 \iff x=4

(we can't accept the negative root because negative lengths make no sense)

7 0
3 years ago
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