Answer:
A' (11, 4), B' (-10, -6), C' (7, -9)
Step-by-step explanation:
Since you are reflecting over the y-axis, you take the opposite of the x value. So if the x is positive, make it negative. If the x is negative, make it positive. The y coordinate stays the same.
Big rectangle
3x-4 (2x+2) = 6x^2-8x+6x-8
=6x^2-2x-8 = 3x^2-x-4
Small rectangle
(X-3) (x-6) = x^2-3x-6x+18
=x^2-9x+18
Big-small= 2x^2+8x-22 is the area of the shaded region
Answer:
Option (C)
Step-by-step explanation:
Given:
In right triangles ΔAED and CEB,
m∠AED = m∠CEB = 90°
DE ≅ BE
AD ≅ BC
To prove:
ΔAED ≅ ΔCEB
Statements Reasons
1). m∠AED = m∠BC = 90° 1). Given
2). DE = BE 2). Given
3). AD = BC 3). Given
4). ΔAED ≅ ΔCEB 4). By HL theorem of congruence
Option (C) is the answer.
A=1/2 bh
1/2 bh=A
h=2A/b
Answer: h=2A/b
Answer:
y= 1/3x+2
Step-by-step explanation:
m= slope
y-intercept= b
