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3 years ago

Find the value of C that completes the square for x^2-2x + C

Mathematics

1 answer:

solniwko [45]3 years ago

3 0

Answer:

C = 1.

Step-by-step explanation:

x^2 - 2x = (x - 1)^2 - 1 so:

x^2 - 2x + C = (x - 1)^2 - 1 + C

So to get a perfect square C must be 1 ( as -1 + 1 = 0):-

(x - 1)^2 - 1 + 1 = (x - 1)^2

Checking this:

x^2 - 2x + 1

= (x - 1)(x - 1) which is a perfect square./

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The lateral area of a cone is 555 \pi cm^2 and the radius is 15.1 what is the slant height?

pishuonlain [190]

We know that
[LA]=pi*r*l
where
LA is the lateral area of the cone
r is the radius
l is the slant height
l=LA/(pi*r)
r=15.1 cm
LA=555*pi cm²
l=(555*pi)/(pi*15.1)----> l=36.75 cm

the answer is
the slant height is 36.75 cm

7 0

2 years ago

Hello please help me as this is the last question on my test and then I’m done so it would be great if u can tell me if the answ

elena55 [62]

Answer:

<em>B) Parallellogram </em>

Step-by-step explanation:

Parallelograms are quadrilaterals where all of the opposite sides are parallel and equal.

Hope this helped, let me know if you need anything else ^-^

5 0

2 years ago

Read 2 more answers

Find the sumofthe geometrical progression of five terms, of which the first term is 7 and the multiplier is 7.Verify that the su

777dan777 [17]

Answer:

The sum of first five term of GP is 19607.

Step-by-step explanation:

We are given the following in the question:

A geometric progression with 7 as the first term and 7 as the common ration.

$a, ar, ar^2,...\\a = 7\\r = 7$

$7, 7^2, 7^3, 7^4...$

Sum of n terms in a geometric progression:

$S_n = \displaystyle\frac{a(r^n - 1)}{(r-1)}$

For sum of five terms, we put n= 5, a = 7, r = 7

$S_5 = \displaystyle\frac{7(7^5 - 1)}{(7-1)}\\\\S_5 = 19607$

The sum of first five term of GP is 19607.

Verification:

$2801\times 7 = 19607$

Thus, the sum is equal to product of 2801 and 7.

7 0

3 years ago

Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74

lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

4 0

3 years ago

Can someone solve -2(+3 + -4 + -8 + +7)? I forgot how to do integers :/

aleksandrvk [35]

Answer:

ur welcome : )

8 0

2 years ago