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4 years ago

The table shows the scores that Ms. Cohen’s students earned on the Chapter 6 and Chapter 7 tests.

Mathematics

2 answers:

Setler79 [48]4 years ago

8 0

The third option is correct - "The percentage of students who earned a score of “needs improvement” on the Chapter 6 test and a score of “proficient” on the Chapter 7 test"

Hope this help :)

kow [346]4 years ago

4 0

Answer: Third option: the percentage of students who earned a score of “needs improvement” on the Chapter 6 test and a score of “proficient” on the Chapter 7 test.

3 represents the number of of students who earned a score of “needs improvement” on the Chapter 6 test.

16=3+13 represents the number total of students who earned a score of “proficient” on the Chapter 7 test.

Then 3/16=0.1875=0.1875*100%=18.75% represents the percentage of students who earned a score of “needs improvement” on the Chapter 6 test and a score of “proficient” on the Chapter 7 test.

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sukhopar [10]

Answer:

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3 years ago

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Solve using Y=Mx+b M=-5 and (-3,-2)

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Given:

M=-5 and (-3,-2).

To find:

The equation in the form $y=mx+b$ .

Solution:

The slope intercept form of a line is

$y=mx+b$ ...(i)

where, m is slope and b is y-intercept.

We have m=-5. Putting m=-5 in (i), we get

$y=-5x+b$ ...(ii)

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3 years ago

5/3 + (-7/6) Reduce to simplest form

son4ous [18]

$\dfrac{5}{3} - \dfrac{7}{6} \\ = \dfrac{10}{6} - \dfrac{7}{6} \\ = \dfrac{3}{6} \\ = \dfrac{1}{2}$

$Answer : \dfrac{1}{2}$

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3 years ago

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Logan genetically engineered a new type of fir tree and a new type of pine tree. The combined height of one fir tree and one pin

shepuryov [24]

Answer:

The types of trees that Logan genetically engineered are fir trees 9 meters tall and pine trees 12 meters tall.

Step-by-step explanation:

Given:

The combined height of one fir tree and one pine tree is 21 meters.

The height of 4 fir trees stacked on top of each other is 24 meters taller than one pine tree.

Now, to find the height of types of trees that Logan genetically engineered.

Let the height of fir tree be $x.$

And let the height of pine tree be $y.$

So, the combined height of both the trees:

$x+y=21\\\\x=21-y\ \ \ .....(1)$

As given, the height of 4 fir trees stacked on top of each other is 24 meters taller than one pine tree.

Thus,

$4x=y+24$

Now, substituting the value of $x$ from equation (1):

$4(21-y)=y+24$

$84-4y=y+24$

Subtracting both sides by 24 we get:

$60-4y=y$

Adding both sides by $4y$ we get:

$60=5y$

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$12=y\\\\y=12\ meters.$

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Now, substituting the value of $y$ in equation to get the height of fir trees:

$x=21-y\\\\x=21-12\\\\x=9\ meters.$

The height of fir trees = 9 meters.

Therefore, the types of trees that Logan genetically engineered are fir trees 9 meters tall and pine trees 12 meters tall.

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3 years ago

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Answer:

Step-by-step explanation:

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