Answer:
7/16=7/16
8/16=1/2
9/16=9/16
10/16=5/8
11/16= 11/16
12/16=3/4
13/16=13/16
14/16=7/8
Step-by-step explanation:
The ones that didn't change are the ones that cannot be simplified :)
To remove the parentheses, you just distribute.
So, it will become 3ax + 3b^2 - 3c +2. I don't think there is any like term in this expression.
Answer:
x= -2y/3
-4y+4y=14
0y= 14
This has no solution.
Step-by-step explanation:
Answer In cases of two equations having two unknown variables the simultaneous method of solving the equations is adopted.
Supposing “0” as the value of “k” we will have the equation as 3x+2y=0
Then separating variable x will give, x= -2y/3
Substituting the value of x into the first equation that is: 6x + 4y = 14
6(-2y/3)+4y=14
Expanding this we get: 6(-2y/3)+4y=14
-4y+4y=14
0y= 14
Thus, no solution.
Given:
The function is:

To find:
The value of
.
Solution:
We have,
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Putting
, we get



On combining like terms, we get


Therefore, the required function is
.