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3 years ago

Platinum can be found in which of the following formations

1 answer:

5 0

Platinum is found in its pure native form, or in platiniridium, a natural alloy of platinum and iridium. Platinum is present in thin sulfide layers in certain maficigneous bodies and is mined in Canada, Russia, South Africa, the USA, Zimbabwe and Australia. Some platinum is obtained as a by-product of copper and nickel processing.

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Calculate and compare the albedo temperature of Mars to Venus. Then compare the two albedo temperatures the planet’s albedo temp

Kryger [21]

Answer:

The albedo temperature for Mars and Venus are 210K and 184 K respectively.Mars albedo temperature is closer to its black body temperature such that the Venus has more albedo.Thus there is a chance that Mars would have had life in their history.

Explanation:

The albedo temperature is given as

$Te =\left [\dfrac{L(1-a)}{ (16\pi \sigma D^2}\right]^{1/4}$

Here

L = Solar luminosity = 3.846*1026 W m-2 K-4

D = distance from Sun

σ = the Stefan-Boltzman constant = 5.6704 * 10-8 W

a is the albedo constant whose value for Mars is 0.250 while for Venus it is 0.900

So the albedo temperature is given as

Venus: 184 K

Mars: 210 K

The black body temperature is given as

$Te =\left [\dfrac{L}{ (16\pi \sigma D^2}\right]^{1/4}$

By substitution of the values, the black body temperature for Venus and Mars are as

Venus: 327 K

Mars: 225 K

Mars albedo temperature is closer to its black body temperature such that the Venus has more albedo.

Thus there is a chance that Mars would have had life in their history.

3 0

3 years ago

What solutions would help decrease flood frequencies and flood sizes that are caused by urbanization

ICE Princess25 [194]

Answer: Fish farming, a type of aquaculture, produces fish through selective breeding to produce a cheap source of protein, reducing the fishing pressure on wild stock fish.

Explanation:

4 0

2 years ago

Imagine that you have obtained spectra for several galaxies and have measured the observed wavelength of a hydrogen emission lin

Lerok [7]

Answer:

A. z (galaxy 1) = -0.00515, z (galaxy 2) = -0.01707, z (galaxy 3) = -0.04008

B. v (galaxy 1) = -0.00517c, v (galaxy 2) = -0.01707c, v (galaxy 3) = -0.0401c

C. d (galaxy 1) = -21 Mpc,d (galaxy 2) = -69.4 Mpc, d (galaxy 3) = -163 Mpc

Explanation:

We begin by listing out the parameters we were given:

λ (obsv) = 656.3 nm, λ (emit 1) = 659.7 nm, λ (emit 2) = 667.7 nm,

λ (emit 3) = 683.7 nm

A) Using the Redshift formula, we have:

z = [λ (obsv) - λ (emit)] ÷ λ (emit)

For galaxy 1:

z = [λ (obsv) - λ (emit 1)] ÷ λ (emit 1)

z = (656.3 - 659.7) ÷ 659.7 = -0.00515

z = -0.00515

For galaxy 2:

z = [λ (obsv) - λ (emit 2)] ÷ λ (emit 2)

z = (656.3 - 667.7) ÷ 667.7 = -0.01707

z = -0.01707

For galaxy 3:

z = [λ (obsv) - λ (emit 3)] ÷ λ (emit 3)

z = (656.3 - 683.7) ÷ 683.7 = -0.04008

z = -0.04008

B) Using the Doppler formula, we have:

(Δλ ÷ λ) = v ÷ c

v = c * (Δλ ÷ λ)

but, z = (Δλ ÷ λ)

⇒ v = c * z

speed of light (c) = 3 x $10^{8}$ m/s

For galaxy 1:

v = c * z

Substitute z into the equation calculated from A) above

v = 3 x $10^{8}$ * (-0.00515)

v = -1.55 x $10^{6}$ m/s

v = -0.00517c

For galaxy 2:

v = c * z

Substitute z into the equation calculated from A) above

v = 3 x $10^{8}$ * (-0.01707)

v = -5.12 x $10^{6}$ m/s

v = -0.01707c

For galaxy 3:

v = c * z

Substitute z into the equation calculated from A) above

v = 3 x $10^{8}$ * (-0.04008)

v = -12.03 x $10^{6}$ m/s

v = -0.0401c

N.B: the negative value of velocity connotes that the galaxies are moving away from us (not towards us)

C) Using Hubbleʹs law, we have:

v = H · d

where:

v = velocity of a galaxy (km/s), d = distance (Mpc),

H = Hubble's constant (km/s/Mpc) = 73.8 km/sec

d = v ÷ H

We use the velocities calculated in B) above

For galaxy 1:

v = -1.55 x $10^{3}$ km/s

d = -1.55 x $10^{3}$ ÷ 73.8

d = -21 Mpc

For galaxy 2:

v = -5.12 x $10^{3}$ km/s

d = -5.12 x $10^{3}$ ÷ 73.8

d = -69.4 Mpc

For galaxy 3:

v = -12.03 x $10^{3}$ km/s

d = -12.03 x $10^{3}$ ÷ 73.8

d = -163 Mpc

N.B: distance cannot be a negative value

4 0

3 years ago

4. The term Pangaea was first used by Alfred Wegener. He proposed the __________ theory.

MA_775_DIABLO [31]

The answer is continental drift.

3 0

3 years ago

Read 2 more answers

The climate of Western Europe is predominately

Anarel [89]

The climate is continental. cold winters and mild summers. hope this helped

6 0

3 years ago

Read 2 more answers