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Lunna [17]
3 years ago
6

If the sides of a triangle have measures 3x + 4, 6x – 1 and 8x + 2, find all possible values of x.

Mathematics
2 answers:
Vitek1552 [10]3 years ago
5 0

Answer:

Answer: x>-4/3 is correct.

Step-by-step explanation:

marissa [1.9K]3 years ago
4 0

Answer: x>-4/3

Step-by-step explanation:All sides must be greater of zero:

3x+4>0

3x> -4 Divide with 3

x> -4/3

6x-1>0

6x>1 Divide with 6

x>1/6

8x+2>0

8x> -2 Divide with 8

x> -2/8

x> -1/4

Least of that numbers is -4/3= -1.3333

x> -4/3 is solution

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Answer:

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schepotkina [342]

Answer:

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Step-by-step explanation:

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If that is wrong, try this. Let's say the questions gives us the fact that x is 20 degrees greater than y.

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3 years ago
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