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Lunna [17]
3 years ago
6

If the sides of a triangle have measures 3x + 4, 6x – 1 and 8x + 2, find all possible values of x.

Mathematics
2 answers:
Vitek1552 [10]3 years ago
5 0

Answer:

Answer: x>-4/3 is correct.

Step-by-step explanation:

marissa [1.9K]3 years ago
4 0

Answer: x>-4/3

Step-by-step explanation:All sides must be greater of zero:

3x+4>0

3x> -4 Divide with 3

x> -4/3

6x-1>0

6x>1 Divide with 6

x>1/6

8x+2>0

8x> -2 Divide with 8

x> -2/8

x> -1/4

Least of that numbers is -4/3= -1.3333

x> -4/3 is solution

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✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ To find the mean, add up all the numbers and divide by the amount of numbers there are. To find the range, subtract the highest number by the  lowest number in the data set.

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