<u>Answer:</u>
Cost of package of paper = 4$
Cost of stapler = 7$
<u>Explanation:</u>
Consider the cost of package of paper = x and that of stapler = y.
Now, we are given that cost of 3 paper packages and 4 staplers = 40$
Hence we get, 3x + 4y = 40 as 1st equation.
we are also given, cost of 5 paper packages and 6 staplers = 62$
Hence, the second equation is 5x + 6y = 62
Now, solving the two equations by method of elimination, we first equate coefficients of any one variable say x by multiplying 1st equation by 5 and second by 3 we get ->
15x + 20y = 200
15x + 18y= 186
Subtracting the two we get y = 7 and substituting this value of y in first equation we get x = 4
which gives the required cost of one paper package = x = 4$
and one stapler = y = 7$
P=2 so 81-p is equal to 81-2 which equals 79
Answer:
51
Step-by-step explanation:
sum of exterior angles = 360
64 + 60 + 69 + 42 + x + x +23 = 360
2x + 258 = 360
2x = 360 - 258
2x = 102
x = 51
Answer: clearly the answer is B hope this helps
Step-by-step explanation: