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Studentka2010 [4]
3 years ago
7

A jar was full of quarters and $1 coins. 2/5 of the coins in the jar were quarters. The rest were $1 coins. There were 10 more $

1 coins than quarters. How many coins were there in the jar altogether?
Mathematics
1 answer:
erma4kov [3.2K]3 years ago
6 0

Answer:

50 coins

Step-by-step explanation:

if there is 1/5 more 1 dollar coins than quarters that means 1/5 of the total number is equal to 10, and if 1/5 is 10 that means 5*10=50 is the total number

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Solve the following:<br> 2x - 2 = 4x + 6
olchik [2.2K]

Answer:

x = -4

Step-by-step explanation:

<u>Step 1:  Subtract 2x from both sides</u>

2x - 2 - 2x = 4x + 6 - 2x

<em>-2 = 2x + 6</em>

<em />

<u>Step 2:  Subtract 6 from both sides</u>

-2 - 6 = 2x + 6 - 6

<em>-8 = 2x</em>

<em />

<u>Step 3:  Divide both sides by 2</u>

-8 / 2 = 2x / 2

<em>-4 = x</em>

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Answer:  x = -4

5 0
3 years ago
If r = 9, b = 5, and g=-6, what does (r+b-g) (b+g) equal?<br> O-20<br> O-8<br> 08<br> O 19<br> O 20
Colt1911 [192]

Answer:

-20...........................

7 0
1 year ago
Which expression is the simplest form of -(2x + y) + 3(x - 4y)?
xenn [34]

Answer:

The answer is x - 13y

Step-by-step explanation:

6 0
3 years ago
Which of the following is the graph of the solution set of t – 4 ≥ 4t + 8 or 3t &gt;14 – 4t?
Stells [14]

Answer:

Option (C)

Step-by-step explanation:

There are two inequalities,

t - 4 ≥ 4t + 8 ------(1)

3t > 14 - 4t ------(2)

By simplifying inequality (1),

t - 4 ≥ 4t + 8

t ≥ 4t + 8 + 4

t ≥ 4t + 12

t - 4t ≥ 12

-3t ≥ 12

t ≤ \frac{12}{(-3)}

t ≤ -4

By solving inequality (2),

3t > 14 - 4t

3t + 4t > 14

7t > 14

t > \frac{14}{7}

t > 2

From the given graphs, Option (C) will be the answer.

4 0
3 years ago
Please factor and find the zeros of each relation (18 marks)
AlekseyPX

Answer:

C. \ \frac{-2}{3} , \ \frac{-4}{5}\\\\D. \ -2, \ -4

Step-by-step explanation:

C.

30x^2 + 44x +16 = 0\\\\2(15x^2 + 22 + 8) = 0\\\\2(15x^2 + 12x + 10x + 8) = 0\\\\2(3x(5x + 4)+2(5x + 4))=0\\\\2((3x + 2)(5x + 4)) = 0\\\\Zeroes : 3x + 2 = 0 => x = \frac{-2}{3}\\

             5x+ 4 = 0 => x = \frac{-4}{5}

D.

10x^2 + 60x +80 = 0\\\\10(x^2 + 6x + 8)= 0\\\\10(x^2 + 4x + 2x + 8)=0\\\\10(x(x+4)+2(x+4))=0\\\\10((x+2)(x+4))=0\\\\Zeroes : x + 2 = 0 =>x = -2

            x + 4 = 0 => x= -4

3 0
3 years ago
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