1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KatRina [158]
3 years ago
12

Someone help me out with this my grade are bad

Mathematics
1 answer:
eduard3 years ago
8 0

Answer:

2 units tall by 1 unit wide

Step-by-step explanation:

On the given rectangle it tell you the conversion to m is 1 unit = 2 m.

The new figure that needs to be drawn has a conversion of 1 unit = 8m.

So, the fist thing we need to do is calculate the m on the width at the height of the original, which is 16 by 8.

looking at this we can now convert this measurement into our new conversion of 1 unit = 8 m. We can do this by dividing the height and width separately.

Ex:

Since 16 is divided by 8 two times so that gives us the answer of 2 units.

8 is divisible by 8 one time so that gives us the width of 1 unit

if this is confusing just think of it like: x=\frac{16}{8} for the height or x = \frac{8}{8} for the width.

You might be interested in
What are the possible dimensions of trapezoid with an area of 100 cm^2?! Need help ASAP
Digiron [165]

Answer:

First, Second and Last Options are correct choices.

Step-by-step explanation:

Regards: Umer

8 0
3 years ago
(5a^2+6a+2)-(7a^2-7a-5)
krok68 [10]

For this case we must simplify the following expression:(5a^ 2 + 6a + 2) - (7a^ 2-7a-5) =

We eliminate the parentheses taking into account that:

- * + = -\\- * - = +

So:

5a ^ 2 + 6a + 2-7a ^ 2 + 7a + 5 =

We add similar terms taking into account that:

Equal signs are added and the same sign is placed.

Different signs are subtracted and the major sign is placed.

5a ^ 2-7a^2 + 6a + 7a +2 +5 =\\-2a ^ 2 + 13a + 7

Answer:

-2a ^ 2 + 13a + 7

8 0
3 years ago
F(x)=17-5x at x=8 Help me plz​
OLEGan [10]
The derivative is -5
4 0
3 years ago
Read 2 more answers
Please answer fast! (10 points)
SIZIF [17.4K]

Answer:

can u show me a picture of this problem.

Step-by-step explanation:

8 0
3 years ago
Your boss tells you that she knows the length of the widgets your company makes is normally distributed with a mean of 25 inches
sp2606 [1]

Answer:

Mean of sampling distribution = 25 inches

Standard deviation of sampling distribution = 4 inches

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 25 inches

Standard Deviation, σ = 12 inches

Sample size, n = 9

We are given that the distribution of length of the widgets is a bell shaped distribution that is a normal distribution.

a) Mean of the sampling distribution

The best approximator for the mean of the sampling distribution is the population mean itself.

Thus, we can write:

\bar{x} = \mu = 25\text{ inches}

b) Standard deviation of the sampling distribution

s = \dfrac{\sigma}{\sqrt{n}} = \dfrac{12}{\sqrt{9}} = 4\text{ inches}

8 0
3 years ago
Other questions:
  • Scientific notation for 0.0008
    7·2 answers
  • What is the median??
    6·2 answers
  • Choose the answer(s) that correctly classify the following expression x^4+400
    11·1 answer
  • Robert is using the following data samples to make a claim about the house values in his neighborhood:
    14·2 answers
  • Five times the larger number is 11 more than three time the smaller number. Also three times the smaller is 16 less four times t
    14·1 answer
  • 15 points !!!! Diameter Radius Area Circumference of 84mm
    15·1 answer
  • A prism with a square base has a height of 15cm and a volume of 735cm3. Find the length of each edge of the base.
    7·1 answer
  • Help HELP HELPPPPPPP PLSSSSSSSSSS
    9·1 answer
  • Can you explain this for me 7-9÷3+6×6×2-4÷2​
    13·1 answer
  • Natasha bought a tennis racket that was marked down in price by 20%. If the racket was originally priced at $125, how much did N
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!