Answer:
x/3 ≤ 5
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Answer:
area: 41.04 cm² ; perimeter 35.8 cm
Step-by-step explanation:
Perimeter of shaded area = 1/4 perimeter of circle + line AC = ¼ * 3.14 * 2 * 12 + √(12² + 12²) = 18.84 + 12√2 cm = 35.8 cm
Area of Shaded Region = 1/4 area of circle - area of triangle = ¼ * 3.14 * 12² - ½ . 12 * 12
= (¼ * 3.14 - ½) * 12² = 41.04 cm²
Answer:
1.25
Step-by-step explanation:
Answer:
10m x 15m
Step-by-step explanation:
You are given some information.
1. The area of the garden: A₁ = 150m²
2. The area of the path: A₂ = 186m²
3. The width of the path: 3m
If the garden has width w and length l, the area of the garden is:
(1) A₁ = l * w
The area of the path is given by:
(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36
Multiplying (2) with l gives:
(3) A₂l = 6l² + 6lw + 36l
Replacing l*w in (3) with A₁ from (1):
(4) A₂l = 6l² + 6A₁ + 36l
Combining:
(5) 6l² + (36 - A₂)l +6A₁ = 0
Simplifying:
(6) l² - 25l + 150 = 0
This equation can be factored:
(7) (l - 10)*(l - 15) = 0
Solving for l we get 2 solutions:
l₁ = 10, l₂ = 15
Using (1) to find w:
w₁ = 15, w₂ = 10
The two solutions are equivalent. The garden has dimensions 10m and 15m.
Answer:
12 units
Step-by-step explanation:
Given that :
R(-3,2)
S(2,2)
T(2,-5).
The total length ;
Distance between two points : √[(x2 - x1)² + (y2 - y1)²]
Distance between R and S :
R = (-3,2)
S(2,2)
√[((2 - (-3))^2 + (2 - 2)^2]
Sqrt(5^2 + 0^2)
D1 = 5 units
Distance between S and T:
S(2,2)
T(2,-5).
D2 = √[(2 - 2)^2 + (-5 - 2)^2]
D2 = sqrt(0^2 + (-7)^2)
D2 = 7 units
Hence, total length = D1 + D2 = (5 + 7) = 12 units
