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3 years ago

Factor as the product of two binomials. x^2-8x+16

Mathematics

2 answers:

sladkih [1.3K]3 years ago

3 0

Answer:

(x-4) (x-4)

Step-by-step explanation:

x^2-8x+16

What 2 numbers multiply to 16 and add to -8

-4*-4 = 16

-4+-4 = -8

(x-4) (x-4)

Mars2501 [29]3 years ago

3 0

Answer:

correct ^

Step-by-step explanation:

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PLEASE ANSWER!!!!!!!!!!

ANTONII [103]

Answer:8%

Step-by-step explanation:

7200x8%=576

1%=72

576 divide by 72= 8%

6 0

4 years ago

Help with number 8 plz and tell me how you did it!

yulyashka [42]

Well, there are 0.25 quarts in a cup so if Krystal makes 18 cups of soup, she can serve 72 guests! because,
0.25 divided by 18 = 72! :)

7 0

3 years ago

A road is inclined at an angle of 5°. After

Scorpion4ik [409]

Answer:

464 feet

Step-by-step explanation:

The Sine of the angle of inclination gives the increase in altitude.

This is because the Sine of an angle is equal to the Opposite side divided by the Hypotenuse side. i.e

Sin Ф = Opposite ÷ Hypotenuse

Sin 5° = O ÷ 5328

0·08716 = O ÷ 5328

Make O the subject and multiply every fraction by 5328

(0·08716/1 × 5328)= (O/5328 × 5328)

464·388 = O

∴ The increase in altitude is 464·388 feet

This is supposed to be to the nearest foot so we round off

464·388 becomes 464 feet

3 0

3 years ago

In a data distribution, the first quartile, the median and the means are 30.8, 48.5 and 42.0

kolbaska11 [484]

Answer:

$Q_3 = 56.45$ --- The third quartile

$Var = 370.18$ -- Variance

Step-by-step explanation:

Given

$Q_1 = 30.8$ -- First quartile

$Q_2 = 48.5$ --- Median

$\bar x = 42$ --- Mean

$Skp = -0.38$ --- Coefficient of skewness

Solving (9): The third quartile $Q_3$

This is calculated from

$Skp = \frac{Q_1 + Q_3 - 2Q_2}{Q_3 - Q_1}$

So, we have:

$-0.38 = \frac{30.8 + Q_3- 2*48.5}{Q_3 - 30.8}$

Cross Multiply

$-0.38 (Q_3 - 30.8)= 30.8 + Q_3- 2*48.5$

Open bracket

$-0.38Q_3 + 11.704= 30.8 + Q_3- 97.0$

Collect like terms

$-0.38Q_3 -Q_3= 30.8 - 97.0- 11.704$

$-1.38Q_3= -77.904$

Divide both sides -1.38

$Q_3 = \frac{-77.904}{-1.38}$

$Q_3 = 56.45$ --- approximated

Solving (b): The variance

First, calculate the standard deviation from:

$3IQR = 4SD$

$IQR= Q_3 - Q_1$

So:

$3IQR = 4SD$

$3(Q_3 - Q_1) = 4SD$

Make SD the subject

$SD = \frac{3}{4}(Q_3 - Q_1)$

$SD = \frac{3}{4}(56.45 - 30.8)$

$SD = \frac{3}{4}*25.65$

$SD = \frac{3*25.65}{4}$

$SD = \frac{76.95}{4}$

$SD = 19.24$

So, the variance is:

$Var = SD^2$

$Var = 19.24^2$

$Var = 370.18$

5 0

3 years ago

Help will give Brainly points

Arlecino [84]

Answer:

x is the hypotenuse

from trigonometry ratios:

$\sin( \theta) = \frac{opposite}{hypotenuse} \\$

consider theta to be 60°

$\sin(60 \degree) = \frac{3}{x} \\ \\ x = \frac{3}{ \sin(60 \degree) } \\ \\ { \underline{ \underline{ \: \: \: x = 3.5 \: \: \: }}}$

6 0

3 years ago