Answer:
CM=20 and CP=12
Step-by-step explanation:
The given triangle ΔACM has the measurements as follows:
m∠C=90°, CP⊥AM, AC=15, AP=9, PM=16.
To Find: CP and CM
We can use Pythagoras theorem to calculate the sides CP and CM.
Pythagoras theorem gives a relation between hypotenuse, base and height/perpendicular of a right angled triangle which is as follows:

where h is hypotenuse of triangle, b is base and p is perpendicular of triangle.
The figure shows that in ΔACM is a right angled triangle at C where,
AM --> hypotenuse
CM --> base
AC --> height
So substituting values into formula:





, which is required answer.
Similarly, we can see that triangle ΔCPM is also a right angled triangle at P and thus Pythagoras theorem can again be applied to calculate CP. Since CM is the side opposite to right angle P, it is the hypotenuse.
So we have,





, which is required answer.
10x=150 so this is the answer it should be because this was the right answer on mine
Answer:
The net outward flux across the boundary of the tetrahedron is: -4
Step-by-step explanation:
Given vector field F = ( -2x, y, - 2 z )


= -2 + 1 -2
= -3
According to divergence theorem;
Flux = 
x+y+z = 2;
Octant
x from 0 to 2
y from 0 to 2 -x
z from 0 to 2-x-y


![= -3 \int\limits^2_0[(2-x)y - \dfrac{y^2}{2}]^{2-x}__0 \ \ dx](https://tex.z-dn.net/?f=%3D%20-3%20%5Cint%5Climits%5E2_0%5B%282-x%29y%20-%20%5Cdfrac%7By%5E2%7D%7B2%7D%5D%5E%7B2-x%7D__0%20%5C%20%5C%20dx)





= -4
Thus; The net outward flux across the boundary of the tetrahedron is: -4
Answer:
6.12 rounded to the nearest tenth is 6.1
45 and 53 are the correct answers on edge.