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3 years ago

Please help I’m confused

Mathematics

1 answer:

Olenka [21]3 years ago

6 0

Answer: 91 degrees

Step-by-step explanation:

you see 89, angle 2 is just a little bit more bigger than 89 so yeah

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I need to know if this H(3,2),J(4,1),K(-2,-4),M(-1,-5) is parallel perpendicular or neither I need to show my work and write my

Shkiper50 [21]

Answer:

Step-by-step explanation:

H(3,2) & J(4, 1)

$Slope = \dfrac{y_{2} -y_{1}}{x_{2}-x_{1}}\\\\=\dfrac{1-2}{4-3}\\\\\\=\dfrac{-1}{1}\\\\= -1$

K(-2,-4) & M(-1 , -5)

$Slope =\dfrac{-5-[-4]}{-1-[-2]}\\\\=\dfrac{-5+4}{-1+2}\\\\= \dfrac{-1}{1}\\\\\\= -1$

Line HJ and KM have same slopes. So, they are parallel

6 0

3 years ago

7 - (-11) = _ <br><br> Please help having trouble with answer

stepladder [879]

Use long addition to evaluate: the answer is 18

8 0

3 years ago

Find the two square roots of each complex number by creating and solving polynomial equations.

son4ous [18]

Answer:

1) w₁=4 - i w₂= -4 + i

2) w₁= 3 - i w₂= -3 + i

3) w₁= 1 + 2i w₂= - 1 - 2i

4) w₁= 2- 3i w₂= -2 + 3i

5) w₁= 5 - 2i w₂= -5 + 2i

6) w₁= 5 - 3i w₂= -5 + 3i

Step-by-step explanation:

The root of a complex number is given by:

$\sqrt[n]{z}=\sqrt[n]{r}(Cos(\frac{\theta+2k\pi}{n}) + i Sin(\frac{\theta+2k\pi}{n}))$

where:

r: is the module of the complex number

θ: is the angle of the complex number to the positive axis x

n: index of the root

1) z = 15 − 8i ⇒ r=17 θ= -0.4899 rad

w₁= $\sqrt{17}(Cos(\frac{-0.4899}{2}) + i Sin(\frac{-0.4899}{2}))$ =4-i

w₂= $\sqrt{17}(Cos(\frac{-0.4899+2\pi}{2}) + i Sin(\frac{-0.4899+2\pi}{2}))$ =-1+i

2) z = 8 − 6i ⇒ r=10 θ= -0.6435 rad

w₁= $\sqrt{10}(Cos(\frac{ -0.6435}{2}) + i Sin(\frac{ -0.6435}{2}))$ = 3 - i

w₂= $\sqrt{10}(Cos(\frac{ -0.6435+2\pi}{2}) + i Sin(\frac{ -0.6435+2\pi}{2}))$ = -3 + i

3) z = −3 + 4i ⇒ r=5 θ= -0.9316 rad

w₁= $\sqrt{5}(Cos(\frac{-0.9316}{2}) + i Sin(\frac{-0.9316}{2}))$ = 1 + 2i

w₂= $\sqrt{5}(Cos(\frac{-0.9316+2\pi}{2}) + i Sin(\frac{-0.9316+2\pi}{2}))$ = -1 - 2i

4) z = −5 − 12i ⇒ r=13 θ= 0.4426 rad

w₁= $\sqrt{13}(Cos(\frac{0.4426}{2}) + i Sin(\frac{0.4426}{2}))$ = 2- 3i

w₂= $\sqrt{13}(Cos(\frac{0.4426+2\pi}{2}) + i Sin(\frac{0.4426+2\pi}{2}))$ = -2 + 3i

5) z = 21 − 20i ⇒ r=29 θ= -0.8098 rad

w₁= $\sqrt{29}(Cos(\frac{-0.8098}{2}) + i Sin(\frac{-0.8098}{2}))$ = 5 - 2i

w₂= $\sqrt{29}(Cos(\frac{-0.8098+2\pi}{2}) + i Sin(\frac{-0.8098+2\pi}{2}))$ = -5 + 2i

6) z = 16 − 30i ⇒ r=34 θ= -1.0808 rad

w₁= $\sqrt{34}(Cos(\frac{-1.0808}{2}) + i Sin(\frac{-1.0808}{2}))$ = 5 - 3i

w₂= $\sqrt{34}(Cos(\frac{-1.0808+2\pi}{2}) + i Sin(\frac{-1.0808+2\pi}{2}))$ = -5 + 3i

6 0

3 years ago

9) A heptagon has 6 exterior angles with measures of 47, 55, 62, 64, 54, and 49. What is the measure of the interior angle adjac

svetlana [45]

Answer:

seventh interior angle=∠x=29°

Step-by-step explanation:

sum of interior angle of polygon is equal to 360°

let seventh angle of heptagon is x

∠x+47°+55°+62°+64°+54°+49°=360°

∠x=360°-(47°+55°+62°+64°+54°+49°)

∠x=360°-331°=29°

∠x=29°

seventh interior angle=∠x=29° answer

6 0

3 years ago

Each leg of a 45°-45°-90° triangle measures 12 cm what is the hypoyenuse

lubasha [3.4K]

To find the hypotenuse in a 45-45-90 triangle multiply the legs by $\sqrt{2}$
So...
The leg is 12 the hypotenuse is 12 $\sqrt{12}$

5 0

3 years ago