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Anton [14]
3 years ago
6

Explain the meaning. A scale on a map is 1mm:20 miles

Mathematics
2 answers:
nlexa [21]3 years ago
5 0

Answer:

Step-by-step explanation:

say you had a grid peice of paper count 20 blocks that 1mm every 20 blocks is 1mm if you had 40 block 2mm and so on hope this helps

ella [17]3 years ago
3 0
Every millimeter on the map is equivalent to 20 miles on eartg
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Draw a number line to represent the street sign below
galina1969 [7]
Its kind of like how it is on a car to tell how fast your going i hoped this helped!

6 0
2 years ago
the straight line L, has equation y=3x-4 The straight line 1, in perpendicular to L, and passes through the point (9.5) Find an
kari74 [83]

Given:

The equation of given line is

y=3x-4

A line is perpendicular to the given line and passes through the point (9,5).

To find:

The equation of the perpendicular line.

Solution:

We have,

y=3x-4

On comparing this equation with slope intercept form y=mx+b, we get

m=3

It means, the slope of the given line is 3.

The product of slopes of two perpendicular lines is -1.

m\times m_1=-1

3\times m_1=-1

m_1=-\dfrac{1}{3}

Point slope form of a line is

y-y_1=m(x-x_1)

Where, m is the slope.

The slope of perpendicular line is -\dfrac{1}{3} and it passes through the point (9,5). So the equation of the line is

y-5=-\dfrac{1}{3}(x-9)

y-5=-\dfrac{1}{3}(x)-\dfrac{1}{3}(-9)

y-5=-\dfrac{1}{3}x+3

Adding 5 on both sides, we get

y-5+5=-\dfrac{1}{3}x+3+5

y=-\dfrac{1}{3}x+8

Therefore, the equation of required line is y=-\dfrac{1}{3}x+8.

5 0
2 years ago
Michael rented a truck for one day. There was a base fee of $18.99, and there was an additional charge of 87 cents for each mile
vazorg [7]
1) 185.16 - 18.99 = 166.17
2) divide 166.17 by 0.87 = 191
3) he drove the truck for 191 miles
4 0
3 years ago
Can someone help me, please!!
love history [14]

Id say its option 3.

5 0
2 years ago
Its scale factoring, please help thanks
svlad2 [7]
45cm I’m sorry that’s not the answer I just need answers for my questions sis
7 0
3 years ago
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