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2 years ago

Help SOS pretty please

Mathematics

1 answer:

Pepsi [2]2 years ago

6 0

Answer:

x = 12

Step-by-step explanation:

Recall: the secant-tangent rule states that when a secant and a tangent meet at an external point of a circle, the product of the secant and the external segment is equal to the square of the tangent segment

(x)(3) = 6² (secant-tangent rule)

3x = 36

Divide both sides by 3

3x/3 = 36/3

x = 12

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A copy machine makes 24 copies per minute. how many copies does it make in 5 minutes and 30 seconds

enot [183]

In 1 minute the copy machine copies = 24
That means
In 60 seconds the copy machine copies = 24
First we need to convert 5 minutes and 30 seconds to seconds
Then
5 minutes and 30 seconds = (5 * 60) + 30
   = 300 + 30
   = 330 seconds
So
In 330 seconds the copy machine will copy = (24/60) * 330
   = 4 * 33
   = 132
So in 5 minutes and 30 seconds the copy machine will copy 132 copies.

6 0

3 years ago

Read 2 more answers

Simplify this expression: -2x + 3 – (5 – 6x). Can someone pls explain how to do this dont just give the awnser

Verizon [17]

Answer:

-2x + 3 – (5 – 6x) = 4x - 2

Step-by-step explanation:

The given expression is :

-2x + 3 – (5 – 6x)

We need to simplify the above expression. First opening the brackets.

-2x + 3 – (5 – 6x) = -2x + 3 – 5 + 6x

Taking like terms together,

= -2x+6x + 3 -5

= 4x - 2

So, the simplified expression is 4x - 2.

5 0

2 years ago

Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))

Marrrta [24]

Answer:

$\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Step-by-step explanation:

$\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine $\frac{1}{c} + \frac{1}{h}$

$\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine the bottom, too.

$=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}$

Apply the fraction rule

$=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}$

Cancel

$=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Therefore, $\frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$