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ratelena [41]
3 years ago
9

A phone company offers two monthly plans. In plan A, the customer pays a monthly fee of $35 and then an additional 9 cents per m

inute of use. In Plan B, the customer pays a monthly fee of $55.70 and then an additional 6 cents per minute of use. For what amounts of monthly phone use will Plan A cost less than Plan B? Use m for the number of minutes of phone use, and solve your inequality for m.
Mathematics
1 answer:
lbvjy [14]3 years ago
5 0

Answer:

Lesser than 6.9 minutes

Step-by-step explanation:

Let m represent the number of minutes of phone use with either plan A or plan B.

In plan A, the customer pays a monthly fee of $35 and then an additional 9 cents(9/100 = $0.09) per minute of use. This means that the total cost of m minutes would be

0.09m + 35

In Plan B, the customer pays a monthly fee of $55.70 and then an additional 6 cents(6/100 = $0.06) per minute of use. This means that the total cost of m minutes would be

0.06m + 55.70

Therefore, for the amounts of monthly phone use for which Plan A will cost less than Plan B, it becomes

0.09m + 35 < 0.06m + 55.70

0.09m - 0.06m < 55.70 - 35

0.03m < 20.7

m < 20.7/3

m < 6.9

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Answer:

The diameter of the pond is 38 m.

The radius of the pond is 19 m.

The area of the pond is 361 m^2.

Step-by-step explanation:

We know that the circumference C of a circle is equal to

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In this case, C is equal to 120 m.

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1.

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or if you mean (3x^3+5x^2+3x-7)+(8x-6x^2+6):

(3x^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=3x^3\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=3x^3-x^2+11x-1

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(8x-4x^2+3)-(x^3+7x^2+3x-8)=\\\\=\underline{8x}\ \underline{\underline{-\ 4x^2}}+3-x^3\ \underline{\underline{-\,7x^2}}\ \underline{-\,3x}+8=\\\\=-x^3-11x^2+5x+10

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