A shop sells 3 different types of tea

Mathematics

1 answer:

lys-0071 [83]3 years ago

8 0

Answer:

The cheapest is the Kenyan tea which costs £1.05 for each 100g.

Step-by-step explanation:

200 g of Kenyan tea costs £2.10

1. Calculate the rate of each gram, by dividing 2.10/200

0.0105 x 100 = £1.05 for each 100g

300 g of Columbian tea costs £3.45

1. Calculate the rate of each gram, by dividing 3.45/300

0.0115 x 100 = £1.15 for each 100g

1. Calculate the rate of each gram, by dividing 1.70/150

150 g of Indian tea costs £1.70

0.01133333333 x 100 = £1.133333333 for each 100g

B) The cheapest is the Kenyan tea which costs £1.05 for each 100g.

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The length of a rectangle is 2 feet less than twice the width. The area of the rectangle is 180 feet squared. Find the length an

Ksenya-84 [330]

Answer:

Width=10

Length=18

Step-by-step explanation:

The length is 2 feet less then twice the width

Let the width be x.

Then the length is 2x -2 based on the given information. Use this to make an equation since it is known that the area is 180feet squared.

x(2x-2)=180

2x^2 - 2x - 180 = 0

2( x^2 - x - 90) = 0

We now have a factorable quadratic.

2(x+9)(x-10)=0

So by zero product property, x=-9, x=10 Since a measure cannot be negative, -9 is an extraneous solution.

So x=10

Then the width is 10 and the length is 18

Hope this helps! Let me know if it is correct!

3 0

4 years ago

<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bx%7D%20%20-%20%20%20%7B3%7D%5E%7Bx%7D%20%20%3D%20%20%20%20%5Csqrt%7B%20%7B6%7D

strojnjashka [21]

Answer:

x = 0

Step-by-step explanation:

${2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {9}^{x } } \\ \\ {2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {( {3}^{2}) }^{x } } \\ \\ {2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {({3)}^{2x}}}\\ \\ {2}^{x} - \cancel{{3}^{x}} = \sqrt{ {6}^{x} } - \cancel{ {3}^{x} } \\ \\ {2}^{x} = \sqrt{ {6}^{x} } \\ squaring \: both \: sides \\ \\ {( {2}^{x} )}^{2} = {(\sqrt{ {6}^{x} })}^{2} \\ \\ {2}^{2x} = {6}^{x} \\ \\ {2}^{2x} = {(2 \times 3)}^{x} \\ \\ {2}^{2x} = {2 ^{x} \times 3}^{x} \\ \\ \frac{ {2}^{2x} }{ {2}^{x} } = 3^{x} \\ \\ {2}^{2x - x} = {3}^{x} \\ \\ {2}^{x} = {3}^{x} \\ \\ \frac{ {2}^{x} }{ {3}^{x} } = 1 \\ \\ \bigg( \frac{2}{3} \bigg)^{x} = 1 \\ \\ \implies \: x = 0 \\ \\ \because \: for \: x = 0 \\ \\ \bigg( \frac{2}{3} \bigg)^{0} = 1$